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polet [3.4K]
3 years ago
9

Fill in the blank.

Chemistry
2 answers:
sweet-ann [11.9K]3 years ago
7 0
Reactivity is the and .....
Diano4ka-milaya [45]3 years ago
7 0
Option a



Your will come for taking your time to read this
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How is matter described?​
Tju [1.3M]

Answer:Matter is defined as anything that has mass and takes up space (it has volume). ... Volume is the amount of space something occupies. Words such as big, little, long, or short are used to describe volumes.

Explanation:

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2 years ago
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What volume of water has the same mass as 9.0m3 of ethyl alcohol?
Triss [41]
This question requires the knowledge of density. 

The density of ethyl alcohol = 789 kg m⁻³
The density of water = 1000 kg m⁻³

Density = Mass / Volume 

By applying ethyl alcohol,
    789 kg m⁻³ = Mass / 0.9 m³
         Mass     = 710.1 kg
hence the mass of 0.9 m³ ethyl alcohol is 710.1 kg.

Then by applying water,
     1000 kg m⁻³ = 710.1 kg / Volume
      Volume        = 0.7101 m³
                          = 0.7 m³
hence the equal water volume is 0.7 m³
8 0
3 years ago
(5 simple questions)
maks197457 [2]
1)a. formation of gas
2)b.energy was transferred
3)c.substances that are used up in a reaction
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3 years ago
Why are questions about philosophy religion not able to be answered through scientific inquiry be specific and use examples to s
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Philosophy bar for CE koala bear nuts
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2 years ago
CaCO3(s)⇄CaO(s)+CO2(g) When heated strongly, solid calcium carbonate decomposes to produce solid calcium oxide and carbon dioxid
rusak2 [61]

Answer:

1.04 mol

Explanation:

CO₂ is produced in a closed 100 L vessel according to the following equation.

CaCO₃(s) ⇄ CaO(s) + CO₂(g)

At equilibrium, the pressure of carbon dioxide remains constant at 1.00 atm.

First, we need to conver the temperature to the absolute scale (Kelvin scale) using the following expression.

K = °C + 273.15

K = 898°C + 273.15

K = 1171 K

Now, we can find the moles of carbon dioxide using the ideal gas equation.

P \times V = n \times R \times T\\n = \frac{P \times V}{R \times T} = \frac{1.00atm \times 100L}{\frac{0.0821atm.L}{mol.K}  \times 1171K} = 1.04 mol

7 0
3 years ago
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