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3 years ago

Fill in the blank.

Chemistry

2 answers:

sweet-ann [11.9K]3 years ago

7 0

Reactivity is the and .....

Diano4ka-milaya [45]3 years ago

7 0

Option a

Your will come for taking your time to read this

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A student conducting the iodine clock experiment accidentally makes an s2o32- stock solution that is too concentrated. how will

cupoosta [38]

Adding (S2O3)2- would affect the reaction mechanism that involves this ion. From the reaction mechanism given above, the equilibrium of step 2 would be affected. Adding the stock solution of (S2O3)2- would shift the equilibrium to the right thus making more products of the said mechanism. Also, the reaction rate of this step would occur faster than the original rate. This is based on Le Chatelier's Prinicple which states that a corresponding change would happen to the equilibrium of a reaction when pressure, concentration of the substances or temperature is changed. So, that after the addition, a color change would appear immediately because I3- would be removed slowly from solution, and would therefore be able to react with starch.

8 0

3 years ago

A sample of table sugar (sucrose, C12H22O11) has a mass of 1.202 g.

Archy [21]

Answer:

a) 0.003512 moles

b) Moles C= 0.04214 moles carbon

Moles H = 0.07726 moles hydrogen

Moles O = 0.03863 moles of oxygen

c) C atoms = 2.54 *10^22 carbon atoms

H atoms = 4.65 *10^22 hydrogen atoms

O atoms = 2.33 *10^22 oxygen atom

Explanation:

Step 1: Data given

Mass of sucrose = 1.202 grams

Molar mass of sucrose = 342.3 g/mol

Step 2: Calculate moles of sucrose

Moles sucrose = Mass sucrose / molar mass sucrose

Moles sucrose = 1.202 grams / 342.3 g/mol

Moles sucrose = 0.003512 moles

Step 3: Calculate moles of each element

For 1 mol of C12H22O11 we have 12 moles of carbon, 22 moles of hydrogen and 11 moles of oxygen

Moles C: 12*0.003512 = 0.04214 moles carbon

Moles H: 22* 0.003512 = 0.07726 moles hydrogen

Moles O: 11* 0.003512 = 0.03863 moles of oxygen

Step 4: Calculate the number of atoms

C atoms = 6.022 *10^23 / mol * 0.04214 moles = 2.54 *10^22 atoms carbon

H atoms = 6.022 * 10^23 / mol * 0.07726 moles = 4.65 *10^22 atoms H

O atoms = 6.022 * 10^23 / mol * 0.03863 moles = 2.33 *10^22 atoms O

0.003512 moles of sucrose containse 6.022 *10^23 * 0.003512 = 2.11 * 10^21 sucrose molecules

7 0

3 years ago

Calculate the adjusted retention times for both pentafluorobenzene and benzene if the elution time for unretained solute is 1.06

vovangra [49]

Answer:

Pentafluorobenzene: 11,92 min

Benzene: 12,14 min

Explanation:

Retention time of pentafluorobenzene is 12,98 min and 13,20 min of benzene.

The adjusted retention time is the time an analyte spends in the column not the stationary phase. As time of unretained solute is 1,06 min the adjusted retention time for an analyte is:

tr' = tr - 1,06min

For pentafluorobenzene:

tr' = 12,98min - 1,06min = 11,92 min

For benzene:

tr' = 13,20 - 1,06min = 12,14 min

I hope it helps!

3 0

3 years ago

An acid is used to bring the pH of a solution from pH 9 to pH 6. How many times more acidic is the final solution than the initi

Papessa [141]

Answer:

The final solution is 1.5 times more acidic than the initial solution

Explanation:

5 0

3 years ago

You might have a flashlight that runs (2) d-cells of 1.5 volts each in series. the bulb is rated for 0.7 amps. what’s its resist

sweet [91]

From Ohm's law, we get the general equation that would relate the voltage, current, and resistance,
V = I x R
where V is voltage, R is resistance, and I is current. Deriving the equation for R
R = V / I
R = (1.5 volts) / (0.7 amps) = 2.14 Ohms

7 0

3 years ago

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