NaOH reacts with CH3COOH in 1:1 molar ratio to produce CH3COONa
NaOH + CH3COOH → CH3COONa + H2O
Mol CH3COOH in 52.0mL of 0.35M solution = 52.0/1000*0.35 = 0.0182 mol CH3COOH
Mol NaOH in 19.0mL of 0.40M solution = 19.0/1000*0.40 = 0.0076 mol NaOH
These will react to produce 0.0076 mol CH3COONa and there will be 0.0182 - 0.0076 = 0.0106 mol CH3COOH remaining in solution unreacted . Total volume of solution = 52.0+19.0 = 71mL or 0.071L
Molarity of CH3COOH = 0.0106/0.071 = 0.1493M
CH3COONa = 0.0076 / 0.071 = 0.1070M
pKa acetic acid = - log Ka = -log 1.8*10^-5 = 4.74.
pH using Henderson - Hasselbalch equation:
pH = pKa + log ([salt]/[acid])
pH = 4.74 + log ( 0.1070/0.1493)
pH = 4.74 + log 0.717
pH = 4.74 + (-0.14)
pH = 4.60.
Answer:
Balanced forces are forces that act in opposite directions and cancel each other out
let me know if you have any other questions
Answer:
The answer is
<h2>5.50</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula
From the question
mass = 22 g
density = 4 g/mL
The volume is
We have the final answer as
<h3>5.50 mL</h3>
Hope this helps you
Answer:
E = 12.92 × 10^(-16) J
Explanation:
Formula for energy is;
E = hc/λ
Where;
h is Planck's constant = 6.63 x 10^(-34) J.s
c is speed of light = 3 × 10^(8) m/s
λ is wavelength = 0.154 nm = 0.154 × 10^(-9) m
E = (6.63 x 10^(-34) × 3 × 10^(8))/(0.154 × 10^(-9))
E = 12.92 × 10^(-16) J
Answer:
2.9 g/cm³
Explanation:
From the question given above, the following data were obtained:
Mass = 236.376 g
Volume = 81.5 cm³
Density =?
Density can be defined as the mass of a substance per unit volume of the substance. It can be expressed mathematically as:
Density = mass /volume
With the above formula, we can obtain the density of the object as shown below:
Mass = 236.376 g
Volume = 81.5 cm³
Density =?
Density = mass /volume
Density = 236.376 / 81.5
Density = 2.9 g/cm³
Thus, the density of the object is 2.9 g/cm³
