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Rufina [12.5K]
3 years ago
5

The chemical equation for the formation of ammonia is unbalanced. 3H2(g) + N2(g) -----> NH3(g) If three molecules of hydrogen

react with one molecule of nitrogen, how many molecules of ammonia would be formed?
Chemistry
2 answers:
mestny [16]3 years ago
8 0

Answer: 2 molecules of ammonia

Explanation:

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

The balanced chemical equation for the formation of ammonia is:

3H_2(g)+N_2(g)\rightarrow 2NH_3

According to stoichiometry,

3 molecules of hydrogen combines with 1 molecule of nitrogen to give 2 molecules of ammonia.

GREYUIT [131]3 years ago
5 0

Answer:

Your answer is 2

Explanation:

I took the test and got it correct

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Read 2 more answers
Aniline, consists of carbon, hydrogen, and nitrogen. Combustion of this yields CO2, H20, and N2 as products. If the combustion o
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The empirical formula : C. C₁₆H₁₅N₂

<h3>Further explanation</h3>

Given

12.5 g of aniline

7.1 grams of H2O

1.48 grams of N2

Required

The empirical formula

Solution

Reaction :

mass H in H₂O :

= 2.1/18 x 7.1 g

= 0.79

mass N = 1.48

mass C :

= 12.5 g-(mass H+mass N)

= 12.5 - (0.79+1.48)

= 10.23

Mol ratio C : H : N =

= 10.23/12 : 0.79/1 : 1.48/14

= 0.853 : 0.79 : 0.106

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5 0
3 years ago
SO2 reacts with O2 to produce SO3. If 86.0 g of SO2 is placed in a reaction vessel along with excess oxygen gas, how many moles
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Answer:

0,72 moles of SO₂ remain

Explanation:

The reaction is:

2SO₂ + O₂ → 2SO₃

Where molecular mass of SO₂ is 64,066g/mol and of SO₃ is 80,066g/mol.

86,0g of SO₂ are:

86,0g × (1mol / 64,066g) = <em>1,34 moles of SO₂</em>.

50,0g of SO₃ are:

50,0g × (1mol / 80,066g) = <em>0,62 moles of SO₃</em>.

Now, as 2 moles of SO₂ produce 2 moles of SO₃, the moles of SO₂ that remain after the reaction are the initial moles of SO₂ - moles of SO₃:

1,34 moles - 0,62 moles =

<em>0,72 moles of SO₂ remain</em>

I hope it helps!

7 0
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