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eduard
3 years ago
8

Why is the pressure so high deep inside the outer planets?

Physics
2 answers:
zlopas [31]3 years ago
7 0

Answer:

they a giant ball of gases, so the answer is they have very large gas masses

Explanation:

trasher [3.6K]3 years ago
6 0

Answer;:

Porquen tienen gavedad

Explanation:

You might be interested in
Air at 80 kPa, 27°C, and 220 m/s enters a diffuser at a rate of 2.5 kg/s and leaves at 42°C. The exit area of the diffuser is
9966 [12]

Answer:

exit velocity = 62 m/s

exit pressure is 98.52332 kPa

Explanation:

given data

pressure p1 = 80 kPa

temperature t1 =  27°C = 300 K

velocity v1 = 220 m/s

temperature t2 =  42°C = 315K

area exit = 370 cm²

lose heat at a rate = 18 kJ/s

gas constant of air = 0.287 kPa·m^3/kg·K.

h1 = 300.19 kJ/kg

h2 = 315.27 kJ/kg

to find out

exit velocity and exit pressure

solution

first we apply here energy balance equation to find out outlet velocity

Einlet = Eoutlet

m(h1 + v1²/2)  = m (h2+v2²/2) +Q

m(v1²-v2²) /2  =  m (h2 -h1) +Q

v2² = v1² - 2Cp Δt - 2Q/m

here  Δt = h2 - h1 and put all value

v2² = 220² - 2(1.005)10³ (15) - 2(18)10³ /2.5

exit velocity = 62 m/s

so

now find outlet pressure that is

p2 = mRT / A2 v2

put value

p2 = 2.5 (287) 315 / (370 10^{-4} 62)

p2 = 98.52332 kPa

exit pressure is 98.52332 kPa

3 0
3 years ago
A compact car has a maximum acceleration of 2.0 m/s2 when it carries only the driver and has a total mass of 1100 kg . you may w
nadya68 [22]

According to Newton`s  law. Force exerted by car,

F = m a = 1100 kg \times 2 m/s^2 = 2200 \ N

After adding an additional 400 kg of mass, the force will be same therefore the acceleration

F = 2200 \ N = (1100 \ kg + 400 \ kg)  a \\\\ a = \frac{2200 \ N}{1500 \ kg} = 1.47 \ m/s^2

Thus, the acceleration after adding the masses is 1.47 \ m/s^2.

4 0
3 years ago
An astronaut notices that a pendulum which took 2.45 s for a complete cycle of swing when the rocket was waiting on the launch p
klio [65]

Answer:

2.84 g's with the remaining 1 g coming from gravity (3.84 g's)

Explanation:

period of oscillation while waiting (T1) = 2.45 s

period of oscillation at liftoff (T2) = 1.25 s

period of a pendulum (T) =2π. \sqrt{\frac{L}{a} }

where

  • L = length
  • a = acceleration

therefore the ration of the periods while on ground and at take off will be

\frac{T1}{T2} =(2π \sqrt{\frac{L}{a1} } ) /  (2π\sqrt{\frac{L}{a2} })

where

  • a1 = acceleration on ground while waiting
  • a2 = acceleration during liftoff

\frac{T1}{T2} = \frac{\sqrt{\frac{L}{a1} }}{\sqrt{\frac{L}{a2} }}

squaring both sides we have

(\frac{T1}{T2})^{2} = \frac{\frac{L}{a1} }{\frac{L}{a2} }

(\frac{T1}{T2})^{2} = \frac{a2}{a1}

assuming that the acceleration on ground a1 = 9.8 m/s^{2}

(\frac{T1}{T2})^{2} = \frac{a2}{9.8}

a2 = 9.8 x (\frac{T1}{T2})^{2}

substituting the values of T1 and T2 into the above we have

a2 = 9.8 x (\frac{2.45}{1.25})^{2}

a2 = 9.8 x 3.84

take note that 1 g = 9.8 m/s^{2} therefore the above becomes

a2 = 3.84 g's

Hence assuming the rock is still close to the ground during lift off, the acceleration of the rocket would be 2.84 g's with the remaining 1 g coming from gravity.

5 0
3 years ago
Two tuning forks are sounded at the same time. which tuning forks will give rise to a beat frequency of 30 hz when sounded toget
SOVA2 [1]

Answer:

300 Hz and 240 Hz

Explanation:

Beat frequency formed by the tuning fork is given by :

f_{beat}=f_1\pm f_2

Here, the beat frequency, f_{beat}=30\ Hz

The frequency of a tuning fork, f_2=270\ Hz

If f_{beat}=f_1+f_2

f_1=f_{beat}-f_2

f_1=30-270

f_1=240\ Hz

If f_{beat}=f_1-f_2

f_1=f_{beat}+f_2

f_1=30+270

f_1=300\ Hz

So, the tuning forks will give rise to a beat frequency are 240 Hz and 300 Hz. Hence, this is the required solution.

6 0
4 years ago
For a solar eclipse to occur which of the following alignments must be necessary
katovenus [111]
Very specific alignment of the Sun, Earth, and Moon. If the Moon is lined up precisely with the Sun from the Earth's point of view, the Moon will block Sunlight from reaching the Earth, causing a solar eclipse.
6 0
3 years ago
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