Work of the force = 10 N
Time required for the work = 50 sec
Height = 7 m
We are given with the value of work and time in the question.
Substitute the values in the formula of power and then you'll get the power required.
We know that,
w = Work
p = Power
t = Time
By the formula,
Given that,
Work (w) = 7 m = 70 Joules
Time (t) = 50 sec
Substituting their values,
p = 70/50
p = 1.4 watts
Therefore, the power required is 1.4 watts.
Hope it helps!
Answer:
The field gets weaker
Explanation:
I’m taking the test right now, hope this helps!!
Answer:
R2 = 300 Ohms
Explanation:
Let the two resistors be R1 and R2 respectively.
RT is the total equivalent resistance.
Given the following data;
R1 = 100 Ohms
RT = 75 Ohms
To find R2;
Mathematically, the total equivalent resistance of resistors connected in parallel is given by the formula;

Substituting into the formula, we have;

Cross-multiplying, we have;
75 * (100 + R2) = 100R2
7500 + 75R2 = 100R2
7500 = 100R2 - 75R2
7500 = 25R2
R2 = 7500/25
R2 = 300 Ohms
Answer:
d
Explanation:
In physics and engineering, a free body diagram (force diagram, or FBD) is a graphical illustration used to visualize the applied forces, moments, and resulting reactions on a body in a given condition.
Answer:
The magnitude of induced emf is 5.4 V
Explanation:
Given:
Magnetic field
T
Area of loop

Time take to reduce loop to zero
sec
To find induced emf we use faraday's law,
Induced emf is given by,

Here minus sign shows lenz law, for finding magnitude of emf we ignore it.
Where
Put the value of flux and find induced emf,


V
Therefore, the magnitude of induced emf is 5.4 V