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Zanzabum
3 years ago
13

What are two ways to increase frictional force?

Physics
1 answer:
Mekhanik [1.2K]3 years ago
7 0
Ways to increase friction - increase the area of contact - increase the roughness of the contact materials - dry up or take away any lubricant - increase the pressure on the contact
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you ask people to rate there depression on a scale of 1 to 10 their respnses are a (n)___in your study. a.variable b.discrete v
8090 [49]
The answer is A) variable. The depression level is a value that varies with the respondents and may inform you about the relationship between depression and other variables, such as alcohol use or sleep habits. It is also likely a discrete variable, since the answer is probably an integer (1, 2, ... 10), rather than a continuous spectrum (virtually any number between 1 and 10). 
6 0
3 years ago
Write a message about an important aspect of life on earth to be sent beyond our solar system
zepelin [54]
We grow crops (plants) on earth, so it's very important for that to go beyond earth because if there is no way to grow crops, we won't get enough nutrients from some synthetic (fake) food. hope I helped! :)
6 0
3 years ago
What is the force that can cause two pieces of iron to attract each other?
Rudiy27

Answer:

B. Magnetic Force

Explanation:

two pieces of irons cannot attract each other unless at least one of them is magnetize. That force is called magnetism.

6 0
3 years ago
Read 2 more answers
20% of injury crashes in 2009 involve the reports of distracted driving. True or false
Ivan

The statement is true.

5 0
2 years ago
Suppose that a comet has a very eccentric orbit that brings it quite close to the Sun at closest approach (perihelion) and beyon
Nutka1998 [239]

Answer:

16.63min

Explanation:

The question is about the period of the comet in its orbit.

To find the period you can use one of the Kepler's law:

T^2=\frac{4\pi}{GM}r^3

T: period

G: Cavendish constant = 6.67*10^-11 Nm^2 kg^2

r: average distance = 1UA = 1.5*10^11m

M: mass of the sun = 1.99*10^30 kg

By replacing you obtain:

T=\sqrt{\frac{4\pi}{GM}r^3}=\sqrt{\frac{4\pi^2}{(6.67*10^{-11}Nm^2/kg^2)(1.99*10^{30}kg)}(1.496*10^8m)^3}\\\\T=997.9s\approx16.63min

the comet takes around 16.63min

8 0
3 years ago
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