An object is placed at a distance 30cm from a thin lenses of power 4 diaptor. Discuss the nature of image
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Mary and her younger brother Alex decide to ride the carousel at the State Fair, Mary's and Alex's angular speed M and tangential speed vM is mathematically given as
Mary's and Alex's angular speed=1.43
Tangential speed mary=3.22 m/s
Tangential speed alex =2.260m/s
<h3>What is Mary's and Alex's angular speed M and tangential speed vM?</h3>Generally, the equation for angular speed is mathematically given as
w = 1.61 rev/see 3.9
Centripetal acc mary = v^2/r
Centripetal acc mary = w^2r
Centripetal acc mary = w^2x 2m
Centripetal acc. of Alex = w²x L.u
Therefore
Hence
tang. speed V=Wr
tang. speed of mary = 1.61x2 = 3.22 m/s
tang. speed of Alex: 1.61X1·4 =2.260m/s
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The equilibrium conditions allow to find the results for the balance forces are:
- F₁ = 225.4 N
- F₂ = 558.6 N
When the acceleration is zero we have the equilibrium conditions for both linear and rotational motion.
∑ F = 0
∑ τ = 0
Where F are the forces and τ the torques.
The torque is the product of the force and the perpendicular distance to the point of support,
The free-body diagrams are diagrams of the forces without the details of the bodies, see attached for the free-body diagram of the system.
We write the translational equilibrium condition.
F₁ - W₁ - W₂ + F₂ = 0
We write the equation for the rotational motion, set our point of origin at scale 1, and the counterclockwise turns are positive.
F₂ 2 - W₁ 1 - W₂ 1.5 = 0
Let's calculate F₂
F₂ =
F₂ = (m g + M g 1.5)/ 2
F₂ =
F₂ = 558.6 N
We substitute in the translational equilibrium equation.
F₁ = W₁ + W₂ - F₂
F₁ = (m + M) g - F₂
F₁ = (12 +68) 9.8 - 558.6
F₁ = 225.4 N
In conclusion using the equilibrium conditions we can find the forces of the balance are:
- F₁ = 225.4 N
- F2 = 558.6 N
Learn more here: brainly.com/question/12830892
