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Luba_88 [7]
2 years ago
11

An object is placed at a distance 30cm from a thin lenses of power 4 diaptor. Discuss the nature of image

Physics
1 answer:
Alexxx [7]2 years ago
6 0

Answer:

nature of image = virtual

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Friction depends on the types of surfaces involved and how hard the surfaces push together. Please select the best answer from t
LenKa [72]

True: Friction depends on the types of surfaces involved and how hard the surfaces push together.

5 0
2 years ago
Describe a situation in which an electron will be affected by an external electric field but will not be affected by an external
irina [24]

Answer:

Explanation:

Situations in which an electron will be affected by an external electric field but will not be affected by an external magnetic field

a ) When an electron is stationary in the electric field and magnetic field , he will be affected by electric field but not by magnetic field. Magnetic field can exert force only on mobile charges.

b ) When the electron is moving parallel to electric field and magnetic field . In this case also electric field will  exert force on electron but magnetic field field will not exert force on electrons . Magnetic field can exert force only on the perpendicular component of the velocity of charged particles.

Situations when electron is affected by an external magnetic field but not by an external electric field

There is no such situation in which electric field will not affect an electron . It will always affect an electron .

6 0
3 years ago
Jimmy is standing 300 feet away from a rocket that is being shot up into the air away from him at an angle of elevation of 70 de
ira [324]

Answer: Vertical height of rocket is 824.24ft

Explanation: see attachment.

Opp/ Adj = Tan 70°

h/ 300 = Tan 70°

h= 300tan 70°

h = 824.24ft

4 0
3 years ago
In unit-vector notation, what is the torque about the origin on a particle located at coordinates (0 m, −3.0 m, 2.0 m) due to fo
irinina [24]

Answer:

The torque about the origin is 2.0Nm\hat{i}-8.0Nm\hat{j}-12.0Nm\hat{k}

Explanation:

Torque \overrightarrow{\tau} is the cross  product between force \overrightarrow{F} and vector position \overrightarrow{r} respect a fixed point (in our case the origin):

\overrightarrow{\tau}=\overrightarrow{r}\times\overrightarrow{F}

There are multiple ways to calculate a cross product but we're going to use most common method, finding the determinant of the matrix:

\overrightarrow{r}\times\overrightarrow{F} =-\left[\begin{array}{ccc} \hat{i} & \hat{j} & \hat{k}\\ F1_{x} & F1_{y} & F1_{z}\\ r_{x} & r_{y} & r_{z}\end{array}\right]

\overrightarrow{r}\times\overrightarrow{F} =-((F1_{y}r_{z}-F1_{z}r_{y})\hat{i}-(F1_{x}r_{z}-F1_{z}r_{x})\hat{j}+(F1_{x}r_{y}-F1_{y}r_{x})\hat{k})

\overrightarrow{r}\times\overrightarrow{F} =-((0(2.0m)-0(-3.0m))\hat{i}-((4.0N)(2.0m)-(0)(0))\hat{j}+((4.0N)(-3.0m)-0(0))\hat{k})

\overrightarrow{r}\times\overrightarrow{F}=-2.0Nm\hat{i}+8.0Nm\hat{j}+12.0Nm\hat{k}=\overrightarrow{\tau}

4 0
2 years ago
The greatest ocean depths on earth are found in the Marianas Trench near the Philippines, where the depth of the bottom of the t
kompoz [17]

Answer:

103063860 Pa

Explanation:

\rho = Density of seawater = 1030 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth at which pressure is being measured = 10.2 km

The gauge pressure is given by

p=\rho gh\\\Rightarrow p=1030\times 9.81\times 10.2\times 10^3\\\Rightarrow p=103063860\ Pa

Therefore, the gauge pressure at a depth of 10.2 km is 103063860 Pa

3 0
3 years ago
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