Answer:
Lustrous is NOT a property of metal
Answer:
B:GRANITE
Explanation:
<em>Granite is typical of a larger family of granitic rocks that are composed mostly of coarse-grained quartz and feldspars in varying proportions. These rocks are classified by the relative percentages of quartz, alkali feldspar, and plagioclase (the QAPF classification), with true granite representing granitic rocks rich in quartz and alkali feldspar. Most granitic rocks also contain mica or amphibole minerals, though a few (known as leucogranites) contain almost no dark minerals.</em>
<em>Granite is typical of a larger family of granitic rocks that are composed mostly of coarse-grained quartz and feldspars in varying proportions. These rocks are classified by the relative percentages of quartz, alkali feldspar, and plagioclase (the QAPF classification), with true granite representing granitic rocks rich in quartz and alkali feldspar. Most granitic rocks also contain mica or amphibole minerals, though a few (known as leucogranites) contain almost no dark minerals.Granite is nearly always massive (lacking any internal structures), hard, and tough. These properties have made granite a widespread construction stone throughout human history.</em>
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Answer:
The source side of the circuit includes all parts of the circuit between the positive side battery post and the load. The load is any device in the circuit that produces light, heat, sound or electrical movement when current is flowing. A load always has resistance and consumes voltage only when current is flowing.
Explanation:
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Answer:
The proportionality constant ( Henry’s constant) = 2.32 * 10^-5 M/kPa
Explanation:
Here in this question, we are concerned with calculating the proportionality constant for this gas.
Mathematically, we can get this from Henry law
From Henry law;
Concentration = Henry constant * partial pressure
Thus Henry constant = concentration/partial pressure
Henry constant = 0.00290 M/125 kPa = 2.32 * 10^-5 M/kPa
Answer: __3__Na2CO3 + __2__Ag3P → __2__Na3P + __3__Ag2CO3
Explanation:
In balancing equations you need to make sure the number of atoms before the reaction should be equal to the number of atoms after the reaction.
Before the reaction: We had 6Na, 9CO, 6Ag and 2p
After the reaction: We have 6Na, 9CO, 6Ag and 2p
And now we are sure that atoms before the reaction are equal to atoms after the reaction
