Answer:
the correct option is D
Explanation:
By keeping the material in an amorphous state, and not promoting its crystallization ... Its internal structure generates that no beam of light is refracted when passing through it, that is why it does not refract any color, therefore it does not manifest any to the simple sight of the human eye.
In addition, all amorphous materials do not have a crystal lattice structure like crystalline crystals, a key example of this type of material is glasses or crystal cups.
The molecules of the amorphous solids are randomly distributed, which means that the macroscopic physical properties of the solid are isotropic, identical in all directions.
Amorphous oxides, thanks to their transparency, solidity and easy to shape into large sheets, are widely used as window glass. Certain organic polymers, by virtue of their strength, light weight and easy processing, are used as structural materials (plastics). There are amorphous semiconductors that are used in computer memories and solar cells thanks to their photovoltaic optical properties and the ease of creating large-area thin films. Amorphous metals are used in transformer cores thanks to their ferromagnetism, low losses and the possibility of forming long tapes. Amorphous chalcogenide is used in xerography by virtue of its photoconductivity and the possibility of forming large area films.
Answer:
Explanation:
.65 M H₂SO₄
H₂SO₄ ⇄ 2H⁺ + SO₄⁻²
C(1-x) 2xC xC
(2xC)². xC /C( 1- x ) = 1.1 x 10⁻²
4 x³C² = 1.1 x 10⁻²
4 . x³ .65² = 1.1 x 10⁻²
x³ = .0065 = 6.5 x 10⁻³
x = 1.867 x 10⁻¹
H⁺ ion concentration =
2xC = 2 x 1.867 x 10⁻¹ x .65
= .2427
pH = - log ( .2427 )
= 0 .615 .
Answer:
Electrons will flow from left to right through the wire.
Pb^2+ ions will be reduccd to Pb metal.
The concentration of Sn2+ ions in the left compartment will increase.
Explanation:
Looking at the relative electrode potentials of the two metals
Sn= -0.14
Pb=-0.13
Tin is expected to function as the anode (left hand half cell) and lead as the anode (right hand half cell) tin oxidizes to sn^2+ hence its concentration increases on the left compartment while lead is reduced to ordinary lead metal on the right hand half cell . since oxidation occurs on the left hand side, electrons flow from left to right.