Explanation:
9.0122 g be Maybe, sorry i don't think so
2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)
65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.
Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)
=0.0282669621 g of O2 left over
Carbon monoxide (CO) is a colorless, odorless, and tasteless gas that is slightly less dense than air. ... Carbon monoxide consists of one carbon atom and one oxygen atom, connected by a triple bond that consists of two covalent bonds as well as one dative covalent bond.
I think it's probably not right.
1. Convert 135g Fe2O3 to moles, divide by 2, and multiply the resulting number by the molar mass of Al
Based on the bond energies given, the enthalpy change for the reaction of is -33 kJ and the reaction is exothermic.
<h3>What is the change in bond energy of a reaction?</h3>
The change in bond energy of a reaction is calculated using the formula below:
- change in bond energy = sum of energies of bonds broken - sum of energies of bonds formed
A reaction is exothermic if the change in bond energy is negative.
A reaction is endothermic if the change in bond energy is positive.
Given the bond enery values above:
sum of energies of bonds broken = 4 × C-H + Br-Br
sum of energies of bonds broken = 4 × 413 + 193 = 1845 kJ
sum of energies of bonds formed = 3 × C-H + C-Br + H-Br
sum of energies of bonds formed = 3 × 413 + 276 + 363 = 1878 kJ
Thus;
change in bond energy = 1845 - 1878 = -33 kJ
- The reaction is exothermic because the change in bond energy is negative.
Therefore, the enthalpy change for the reaction of is -33 kJ and the reaction is exothermic.
Learn more about enthalpy change at: brainly.com/question/11628413
