Identify the following compound from its IR and proton NMR spectra. C5H6O: IR: 3300 (sharp), 2102, 1634 cm–1 NMR: δ 3.10 (1H, d,
J = 2 Hz); δ 3.79 (3H, s); δ 4.52 (1H, doublet of doublets, J = 6 Hz and 2 Hz); δ 6.38 (1H, d, J = 6 Hz)
1 answer:
Answer:
trans-1-metoxy-1-buten-3-yne
Formula:HC_CCH=CHOCH3
structural diagram is attached
Explanation:
1-METHOXY-1-BUTEN-3-YNE, MIXTURE OF CIS- & TRANS-ISOMERS 98%
CAS No.3685-19-6
Chemical Name:1-METHOXY-1-BUTEN-3-YNE, MIXTURE OF CIS- & TRANS-ISOMERS 98%
CBNumber:CB91499271
Molecular Formula:HC_CCH=CHOCH3
Formula Weight:0
MOL File:Mol file
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Answer:
44 g
Explanation:
The formula for the number of moles (n) is equal to .
Since we need to find the mass, we derive it from the formula of the number of moles and we get that mass = n x molecular weight .
The molecular weight of = 12 g/mol (from the carbon) + 19x4 g/mol (from the 4 fluorine atoms)= 88 g/mol
We plug in the numbers in the derived formula for the mass and we get :
mass = n x molecular weight = 0.5 mol x 88 g/mol = 44 g