Question

What is the inverse of h?

Answer 1

H(x) = 6x + 1

turn h(x) into y

y = 6x + 1

switch the x and the y

x = 6y + 1

solve for y

6y = x - 1
y = 1/6x - 1/6
y = 1/6(x - 1)

now stick the inverse notation in for y....h -1(x)

h-1(x) = 1/6(x - 1).....I think I did that right