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kap26 [50]
3 years ago
15

Using wolfram alpha or some other reference, determine which of these elements would be liquid at 525 k (assume samples are prot

ected from air):
Chemistry
1 answer:
romanna [79]3 years ago
3 0
The choices for this problem are bismuth, Bi; platinum, Pt; selenium, Se; calcium, Ca and copper, Cu. I think the correct answer would be selenium. The melting point of bismuth is at a temperature of 544.4 Kelvin. At a temperature of 525 K, it would exist as solid. Platinum melts at 2041.1 K. At 525 K, platinum would be in solid form. Selenium has a melting point at 494 K so that at a temperature of 525 K, it would exist in its liquid state. Calcium has a melting point of 1112 K so it would exist as solid at 525 K. Copper has a melting point at 1358 K, so it would still exist as solid at a temperature of 525 K. Therefore, the answer would only be selenium.
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Only_________are involved in forming chemical bonds betwen two atoms
olchik [2.2K]

C)

<em>O</em><em>n</em><em>l</em><em>y</em><em> </em><em>v</em><em>a</em><em>lence</em><em> </em><em>electrons</em><em> </em><em>are involved in forming chemical bonds betwen two atoms</em><em>.</em>

Hope this helped you- have a good day bro cya)

4 0
2 years ago
Calculate the percent ionic, the percent covalent, and the bond length (in picometers) of a chemical bond between phosphorus and
kirza4 [7]

Answer:

The correct option is;

4 percent ionic, 96 percent covalent, 222 pm

Explanation:

The parameters given are;

Phosphorus:

Atomic radius = 109 pm

Covalent radius = 106 pm

Ionic radius = 212 pm

Electronegativity of phosphorus = 2.19  

Selenium:

Atomic radius = 122 pm

Covalent radius = 116 pm

Ionic radius = 198 pm

Electronegativity of selenium= 2.55  

The percentage ionic character of the chemical bond between phosphorus and selenium is given by the relation;

Using Pauling's alternative electronegativity difference method, we have;

\% \, Ionic \ Character = \left [18\times (\bigtriangleup E.N.)^{1.4}  \right ] \%

Where:

Δ E.N. = Change in electronegativity = 2.55 - 2.19 = 0.36

Therefore;

\% \, Ionic \ Character = \left [18\times (0.36)^{1.4}  \right ] \% = 4.3 \%

Hence the percentage ionic character = 4.3% ≈ 4%

the percentage covalent character = (100 - 4.3)% = 95.7% ≈ 96%

The bond length for the covalent bond is found adding the covalent radii of both atoms as follows;

The bond length for the covalent bond = 106 pm + 116 pm = 222 pm.

The correct option is therefore, 4 percent ionic, 96 percent covalent, 222 pm.

4 0
3 years ago
What is the molarity of a solution containing 5 moles of HCl in 2.5 L of solution? Be sure to include the formula for calculatin
beks73 [17]

Answer:

\boxed{\text{2 mol/L}}

Step-by-step explanation:

c = \dfrac{ \text{moles} }{ \text{litres}}\\\\c = \dfrac{n }{V }

Data:

n = 5 mol

V = 2.5 L

Calculation:

c = \dfrac{ \text{5 mol} }{\text{2.5 L}} = \text{2 mol/L}

The molar concentration of the solution is \boxed{\textbf{2 mol/L}}.

6 0
3 years ago
Unknown # 41
sveta [45]

Answer:

KI

Explanation:

From the question, we can see that a qualitative analysis of the compound shows that it has a lilac flame colour. The lilac flame colour corresponds to the potassium ion (K^+).

Again, the test of addition of HNO3(aq) and AgNO3(aq) to a solution is a test for halogens. If the result is a green precipitate, then the ion present is the iodide ion (I^-).

Hence, the compound must be KI.

4 0
2 years ago
Draw and name the isomers of c4h9NH2
AveGali [126]

Answer:

yhnjulllljjghbbjygbnk

6 0
2 years ago
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