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kap26 [50]
3 years ago
15

Using wolfram alpha or some other reference, determine which of these elements would be liquid at 525 k (assume samples are prot

ected from air):
Chemistry
1 answer:
romanna [79]3 years ago
3 0
The choices for this problem are bismuth, Bi; platinum, Pt; selenium, Se; calcium, Ca and copper, Cu. I think the correct answer would be selenium. The melting point of bismuth is at a temperature of 544.4 Kelvin. At a temperature of 525 K, it would exist as solid. Platinum melts at 2041.1 K. At 525 K, platinum would be in solid form. Selenium has a melting point at 494 K so that at a temperature of 525 K, it would exist in its liquid state. Calcium has a melting point of 1112 K so it would exist as solid at 525 K. Copper has a melting point at 1358 K, so it would still exist as solid at a temperature of 525 K. Therefore, the answer would only be selenium.
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In a recent Grand Prix, the winner completed the race with an average speed of 299.8 km/h. What was his speed in miles per hour,
scoundrel [369]

Answer :

(a) The speed is, 186.287 mi/hr

(b) The speed is, 83.277 m/s

(c) The speed is, 273.22 feet/s

Explanation :

(a) We are given the speed is, 299.8km/hr

As we know that,

1km=\frac{1}{1.60934}mi

By using both the conversion, we get:

299.8km/hr

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The speed is, 186.287 mi/hr

(b) We are given the speed is, 299.8km/hr

As we know that,

1km=1000m

and,

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By using both the conversion, we get:

299.8km/hr

\Rightarrow \frac{299.8km}{1hr}\times \frac{1000m}{1km}\times \frac{1hr}{3600s}

\Rightarrow 83.277m/s

The speed is, 83.277 m/s

(c) We are given the speed is, 299.8km/hr

As we know that,

1km=3280.84feet

and,

1hr=3600s

By using both the conversion, we get:

299.8km/hr

\Rightarrow \frac{299.8km}{1hr}\times \frac{3280.84feet}{1km}\times \frac{1hr}{3600s}

\Rightarrow 273.22feet/s

The speed is, 273.22 feet/s

3 0
4 years ago
What is the Mr of a substance where 1 mole has a mass of 11 g?
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Answer:

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12 grams of carbon-12 (i.e., 6.023 X 1023).

Explanation:

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laboratory stock solution is 1.50 M NaOH. Calcul. Show transcribed image text A laboratory stock solution is 1.50 M NaOH. Calculate the volume of this stock solution that would be needed to prepare 300. ml
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