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Rufina [12.5K]
3 years ago
11

1. A sample of argon at a pressure of 785 mm Hg is transferred from a 125 ml dask to a 15 ml

Chemistry
1 answer:
disa [49]3 years ago
6 0

Answer:

The pressure of argon inside the 155 ml flask is approximately <u>633 mm Hg.</u>

Explanation:

Given:

The temperature is constant. So, the process is isothermal.

Initial pressure of argon is, P_1=785\ mm\ Hg

Initial volume of argon is, V_1=125\ ml

Final volume of argon is, V_2=155\ ml

Final pressure of argon is, P_2=?

Now, as per Boyle's law, for an isothermal process, the product of pressure and volume is always a constant or PV=constant. Therefore, we can write it as:

P_1V_1=constant\\P_2V_2=constant\\\therefore P_1V_1=P_2V_2

Rewriting the above in terms of P_2, we have:

P_2=\frac{P_1V_1}{V_2}

Plug in 785 for P_1, 125 for V_1, 155 for V_2 and solve for P_2. This gives,

P_2=\frac{785\times 125}{155}\\P_2=633.06\approx 633\ mm\ Hg

Therefore, the pressure of argon inside the 155 ml flask is approximately 633 mm Hg.

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