Answer:
a. Time=25seconds
b.distance=1041.67m
Explanation:
a.The equation for in terms of m/s is
after conversion.
To find when speed reaches 300km/hr=83.33m/s, we find and solve for
b. From a, above we already have our t=25seconds as the time it takes before the plane is airborne.
#To find distance travelled in that time , we substitute for in our distance equation:
Hence the distance of the plane before it gets airborne is 1041.67m
Hi there!
We can use Biot-Savart's Law for a moving particle:
B = Magnetic field strength (T)
v = velocity of electron (0.130c = 3.9 × 10⁷ m/s)
q = charge of particle (1.6 × 10⁻¹⁹ C)
μ₀ = Permeability of free space (4π × 10⁻⁷ Tm/A)
r = distance from particle (2.10 μm)
There is a cross product between the velocity vector and the radius vector (not a quantity, but specifies a direction). We can write this as:
Where 'θ' is the angle between the velocity and radius vectors.
a)
To find the angle between the velocity and radius vector, we find the complementary angle:
θ = 90° - 60° = 30°
Plugging 'θ' into the equation along with our other values:
b)
Repeat the same process. The angle between the velocity and radius vector is 150°, and its sine value is the same as that of sin(30°). So, the particle's produced field will be the same as that of part A.
c)
In this instance, the radius vector and the velocity vector are perpendicular so
'θ' = 90°.
d)
This point is ALONG the velocity vector, so there is no magnetic field produced at this point.
Aka, the radius and velocity vectors are parallel, and since sin(0) = 0, there is no magnetic field at this point.
Let at any instant of time the speed is vo and the angle made by the bike with the horizontal is given
now we have
component of speed in x direction given as
component of speed in y direction will be
now from above two equations we can say that here
= angle with the horizontal at any instant
and since here it is a sine curve so we know that
so we have slope of graph