Answer:
Sorry this isn’t going to be any help. You don’t have any statement that I’m able to see.
Explanation:
Answer:
C) 0m
Explanation:
Since at the end of the day, it was not displaced
Displacement ti's a vector quantity
Answer:
12.0 V
Explanation:
Data :
Potential difference due to a single charge (+Q), E = 3.0 V
The Electric potential for the system of charges is given as:
![E=\frac{1}{4\pi \epsilon_o}[\Sigma\frac{Q}{r}]](https://tex.z-dn.net/?f=E%3D%5Cfrac%7B1%7D%7B4%5Cpi%20%5Cepsilon_o%7D%5B%5CSigma%5Cfrac%7BQ%7D%7Br%7D%5D)
for single charge, E = 3.0 V =
->eq(1)
And for 4 charges:
-eq(2)
from eq(1) and (2) we have
E = 4 × 3.0 V = 12 V
Answer:
The pressure in the water is 
Explanation:
Given that,
Depth = 101 m
Let P be the pressure at the bottom of water at a depth
We need to calculate the pressure in water
Using formula of pressure

Where,
= atmospheric pressure
= pressure in water
Put the value of
in to the formula

Put the value into the formula


Hence, The pressure in the water is 