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Genrish500 [490]
3 years ago
14

What takes up the vast majority of space in an atom?

Chemistry
1 answer:
yKpoI14uk [10]3 years ago
7 0

The answer is: a relatively large electron cloud.

Atom is composed of the nucleus and the electron cloud.

Protons (positive particles) and neutrons (neutral particles) are in the nucleus of an atom and electrons (negative particles) are in the electron cloud.

Nucleus is in the centar of the atom atom and electron cloud is surrounding it.

Atoms have their mass concentrated in a very small nucleus.


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A generator is not required to generate electrical energy when which of the following energy sources is used?
Anon25 [30]

Answer:

think it's C but my gut is telling me A

Explanation:

5 0
3 years ago
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So if there is 16 protons and 16 neutrons what would be the charge right now?​
sveta [45]

Answer:

16

Explanation:

Protons have a positive net charge,

Neutrons being neutral don't have a net charge.

Each proton is one extra net charge if you have 16 of them and the neutrons don't affect your net charge you will have 16.

6 0
3 years ago
Which law states that the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pr
leonid [27]
The law that states the volume and absolute temperature of a fixed quantity of gas are directly proportional under constant pressure conditions would be the Charles Law. It <span>is an experimental gas </span>law<span> that describes how gases tend to expand when heated. Hope this answers the question.</span>
6 0
3 years ago
Determine the enthalpy for this reaction: Al(OH)3(s)+3HCl(g)→AlCl3(s)+3H2O(l)
ivanzaharov [21]
<span>Important information to solve the exercise :
Substance ΔHf (kJ/mol):
HCl(g)= −92.0 </span><span>kJ/mol
Al(OH)3(s)= −1277.0 </span><span><span>kJ/mol
</span> H2O(l)= −285.8 </span><span>kJ/mol
AlCl3(s) =−705.6 </span><span>kJ/mol

</span><span>Al(OH)3(s)+3HCl(g)→AlCl3(s)+3H2O(l)
    reactants                         products

products- reactants:</span><span>

(−705.6) + (3 x −285.8) - ( −1277.0 ) - (3 x −92.0 ) = - 10.0 </span>kJ per mole at 25°C
<span>
</span>






6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cboxed%7B%5Crm%7BChemistry%20%5C%20Question%7D%7D" id="TexFormula1" title="\boxed{\rm{Chemis
shepuryov [24]

Answer:

Explanation:

All three lighter boron trihalides, BX3 (X = F, Cl, Br), form stable adducts with common Lewis bases. Their relative Lewis acidities can be evaluated in terms of the relative exothermicities of the adduct-forming reaction. Such measurements have revealed the following sequence for the Lewis acidity: BF3 < BCl3 < BBr3 (in other words, BBr3 is the strongest Lewis acid).

This trend is commonly attributed to the degree of π-bonding in the planar boron trihalide that would be lost upon pyramidalization (the conversion of the trigonal planar geometry to a tetrahedral one) of the BX3 molecule, which follows this trend: BF3 > BCl3 > BBr3 (that is, BBr3 is the most easily pyramidalized). The criteria for evaluating the relative strength of π-bonding are not clear, however. One suggestion is that the F atom is small compared to the larger Cl and Br atoms, and the lone pair electron in the 2pzorbital of F is readily and easily donated, and overlaps with the empty 2pz orbital of boron. As a result, the [latex]\pi[/latex] donation of F is greater than that of Cl or Br. In an alternative explanation, the low Lewis acidity for BF3 is attributed to the relative weakness of the bond in the adducts F3B-L.

3 0
3 years ago
Read 2 more answers
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