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3 years ago

What takes up the vast majority of space in an atom?

Chemistry

1 answer:

yKpoI14uk [10]3 years ago

7 0

The answer is: a relatively large electron cloud.

Atom is composed of the nucleus and the electron cloud.

Protons (positive particles) and neutrons (neutral particles) are in the nucleus of an atom and electrons (negative particles) are in the electron cloud.

Nucleus is in the centar of the atom atom and electron cloud is surrounding it.

Atoms have their mass concentrated in a very small nucleus.

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According to the following reaction, how many grams of potassium phosphate will be formed upon the complete reaction of 29.6 gra

Ugo [173]

Answer:

There is 37.36 grams of K3PO4 produced

Explanation:

Step 1: Data given

Mass of H3PO4 = 29.6 grams

KOH is in excess

Molar mass of KOH = 56.11 g/mol

Molar mass of H3PO4 = 97.99 g/mol

Step 2: The balanced equation

3KOH(aq) + H3PO4(aq) ⇔ K3PO4(aq)+3H2O(l)

Step 3: Calculate mass of KOH

Mass KOH = mass KOH / molar mass KOH

Mass KOH = 29.6 grams / 56.11 g/mol

Mass KOH = 0.528 moles

Step 4: Calculate moles of K3PO4

Since KOH is the limiting reactant, We need 3 moles of KOH for each moles of H3PO4, to produce 1 mole of K3PO4 and 3 moles of H2O

For 0.528 moles of KOH we'll have 0.528/3 = 0.176 moles of K3PO4

Step 5: Calculate mass of K3PO4

Mass K3PO4 = moles K3PO4 * molar mass K3PO4

Mass K3PO4 = 0.176 moles * 212.27 g/mol

Mass K3PO4 = 37.36 grams

There is 37.36 grams of K3PO4 produced

8 0

3 years ago

How many molecules are there in 4dm³ of nitrogen gas

daser333 [38]

There are 1.078 x 10²³ molecules

<h3>Further explanation</h3>

Given

4 dm³ = 4 L Nitrogen gas

Required

Number of molecules

Solution

Assumptions on STP (1 atm, 273 K), 1 mol gas = 22.4 L, so for 4 L :

mol = 4 : 22.4

mol = 0.179

1 mol = 6.02 x 10²³ particles(molecules, atoms)

For 0.179 :

= 0.179 x 6.02 x 10²³

= 1.078 x 10²³

5 0

2 years ago

Fluorine and Nitrogen react to form a covalent molecule. Which best describes the molecule they will make?

mafiozo [28]

I think a is the correct answer

7 0

3 years ago

Calculate the hydroxide ion concentration of a 0.200 M solution of HCIO4

Aleksandr [31]

The concentration of hydroxide ion is 5 $\times$ 10^ − 14 M.

<u>Explanation:</u>

Consider the equilibrium of this acid's dissociation,

H C l O 4 ⇌ H + + C l O 4 -

Moreover, let's assume that H C l O 4 is a strong acid and will fully dissociate.

Hence,

[ H + ] = 0.20 M

Now, recall,

K w = [ H + ] [ O H − ] = 1.0 $\times$ 10 ^− 14

Hence,

⇒ [ O H − ] = K w / [ H + ] = 5 $\times$ 10^ − 14 M.

7 0

3 years ago

A 32.8 g iron rod, initially at 22.4 C, is submerged into an unknown mass of water at 63.1 C, in an insulated container. The fin

laila [671]

Answer:

mass water = 32.4 g

Explanation:

specific heat iron = 0.450 J/g°C

specific heat water = 4.18 J/g°C

32.8 x 0.450 ( 59.1 - 22.4) + mass water x 4.18 ( 59.1- 63.1)=0

541.7 - mass water x 16.7 = 0

mass water = 32.4 g

3 0

2 years ago