If there weren't any predators, the population of prey would increase and they would starve due to too many mouths to feed.
Answer:
its shorter than a regular one
Explanation:
the only reason is simply because it is shorter
Answer:
The correct answer is "Iron and oxygen act as Fe3+ and O2− ions respectively, forming rust (Fe₂O₃) in the presence of water by the formation of an ionic bond".
Explanation:
Rust is formed when iron reacts with oxygen in the presence of water (either if the iron is submerged or exposed to moisture in the air), forming the chemical compound Fe₂O₃. The presence of water is needed for rust formation because iron and oxygen act as ions when they are exposed to water, particularly Fe3+ and O2− ions respectively. The bond formed between these two elements are ionic bonds, because it is comprised of the reaction between a metal (iron) and a non-metal (oxygen).
Answer:
Mass = 73.73 g
Explanation:
Given data:
Mass of Mg used = 24.48 g
Mass of HCl used = ?
Mass of hydrogen gas produced = 2.04 g
Mass of Magnesium chloride produced = 96.90 g
Solution:
Chemical equation:
Mg + 2HCl → MgCl₂ + H₂
Number of moles of Mg:
Number of moles = mass/ molar mass
Number of moles = 24.48 g/ 24.305 g/mol
Number of moles = 1.01 mol
Now we will compare the moles of Mg with HCl from balance chemical equation.
Mg : HCl
1 ; 2
1.01 : 2/1× 1.01 = 2.02 mol
Mass of HCl react:
Mass = number of moles × molar mass
Mass = 2.02 × 36.5 g/mol
Mass = 73.73 g
Considering the ideal gas law, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.
Ideal gases are a simplification of real gases that is done to study them more easily. It is considered to be formed by point particles, do not interact with each other and move randomly. It is also considered that the molecules of an ideal gas, in themselves, do not occupy any volume.
An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law, an equation that relates the three variables if the amount of substance, number of moles n, remains constant and where R is the molar constant of the gases:
P× V = n× R× T
In this case, you know:
- P= 2 atm
- V= ?
- n=
being 2g/mole the molar mass of H2, that is, the amount of mass that a substance contains in one mole. - R= 0.082
- T= 353 K
Replacing:
2 atm× V = 4.745 moles× 0.082× 353 K
Solving:
V = (4.745 moles× 0.082× 353 K)÷ 2 atm
<u><em>V= 68.67 L</em></u>
Finally, a sample weighing 9.49 g occupies 68.67 L at 353 K and 2.00 atm.
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