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emmainna [20.7K]
3 years ago
14

Comparing ultraviolet photons to radio photons, we can say that the ultraviolet photons have ______ energy, ______ frequency, an

d ______ wavelength than do radio photons.
Physics
1 answer:
guajiro [1.7K]3 years ago
7 0

Answer:

Energy of ultra violet photons < Energy of radio waves

Wavelength of ultra violet photons > Wavelength of radio waves

Explanation:

The increasing order of the wavelength is given by

Gamma rays

x rays

Ultra violet rays

Visible radiations

Infrared rays

micro waves

Radio waves

So, ultra violet rays has larger wavelength than radio waves.

As we know that the energy is inversely proportional to the wavelength.

So, the energy of radio waves is more than the energy of ultra violet waves.

Energy of ultra violet photons < Energy of radio waves

Wavelength of ultra violet photons > Wavelength of radio waves

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Zigmanuir [339]

Answer:

Explanation:

We know that, the force responsible for circulating in circular path is the centripetal force given by the force on charged particle due to magnetic field.

Here the charge is antiproton is

p = -1.6 * 10⁻¹⁹C

the speed of proton is given by 1.5 * 10 ⁴ m/s

the magnetic field is B = 4.5 * 10⁻³T

we have force due to magnetic field is equal to centripetal force

Bqv = mv² / r

Bq = mv / r

r = \frac{mv}{Bq} \\\\r=\frac{mv}{Bq} \\\\r=\frac{1.67 \times 10^-^2^7\times 1.5 \times 10^4}{4.5 \times 10^-^3\times 11.6\times 10^-^1^9} \\\\r=347.9\times 10^-^4\\\\r=3.479cm

The diameter d of the vacuum chamber have to allow these antiprotons to circulate without touching the walls is

d = 2r

d = 2 * 3.479

d = 6.958

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7 0
3 years ago
A bird, accelerating from rest at a constant rate, experiences a displacement of 28 m in 11 s. what is the final velocity after
frutty [35]
Let's see what variables we've got first. Hmmm. We have:

Displacement, d = 28 m
Time taken, t = 11 s
Initial velocity, u = 0 m/s (at rest)

And now we need to find the final velocity, v. Among the 4 (or 5) equations of motions, there's no equation that will let us simply plug in the values and give an answer sigh. But fear not! We'll do it in steps.

I'm going to pick one of the motion equation to find more information:

d = ut +  \frac{1}{2} a {t}^{2}

I know everything except for a in this one, so I I'll use this! After plugging in values, I get a = 0.4628 m/s^2.

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v = u + at

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The distance between stars is typically measured in
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Read 2 more answers
The windshield of a speeding car hits a hovering insect. Consider the time interval from just before the car hits the insect to
HACTEHA [7]

Answer:

A. False

B True

C. False

D.False

E. True

F. False

G. False

H. False

I. True

Explanation:

A. False: The system being analyzed consists of the bug and the car.  These are the two bodies involved in the collision.

B. True: The system being analyzed consists of the bug and the car

C. False: The magnitudes of the change in velocity are different from the car and the bug. The velocity of the bug changes from 0 to the velocity of the car, while there is no noticeable change in the velocity of the car

D.False: There is barely any change in the momentum of the car since the mass of the bug is very small.

E. True: Since the mass of the bug is small, and was initially at rest, the magnitude of the change in monentum will be large because the new velocity will be that of the car.

F. False: The system being analyzed consists of the bug and the car. Those are the two bodies involved in the collision

G. False: The car barely changes in velocity since the mass of the bug is small.

H. False: The car barely changes in momentum because the collision does not affect its speed so much. on the other hand the momentum change of the bug is large since its mass is small.

I. True: The bug which was initially at rest will begin moving with the velovity of the speeding car, while the car barely changes in its velocity

5 0
3 years ago
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