A 60-watt light bulb has a voltage of 120 volts applied across it and a current of 0.5 amperes flows through the bulb. What is t
he resistance of the light bulb?
1 answer:
Answer: 240ohms
Explanation: P=IV
P=60watts
I=0.5A
V=120volts
From ohms law
V=IR
R=V/I
R=120/0.5
R= 240ohms
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