Calculate the solubility of silver chloride in 0.17M AgNO3. (Ksp=1.8E-10)

1 answer:

4 0

As the given equation is
AgNO3 = Ag+ + NO3-
split it then derive the
the Ksp expression.

Ksp = [Ag+] [NO3-]

Since there is 1:1 molar ratio,so by applying values

1.8E^-10 = (s)(s)
1.8E^-10 = s^2
s=1.34 x 10^-5 M
this is the solubility of silver chloride
hope it helps

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