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sleet_krkn [62]
3 years ago
6

Calculate the solubility of silver chloride in 0.17M AgNO3. (Ksp=1.8E-10)

Chemistry
1 answer:
Zina [86]3 years ago
4 0
  As the given equation is
AgNO3 = Ag+ + NO3-
split it then derive the
 the Ksp expression.

Ksp = [Ag+] [NO3-]

Since there is 1:1 molar ratio,so by applying values

<span>1.8E^-10 = (s)(s)
</span><span>1.8E^-10 = s^2
</span><span>s=1.34 x 10^-5 M
this is the solubility of silver chloride
hope it helps</span>
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