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Simora [160]
3 years ago
9

Describe, in detail, nuclear fission and nuclear fusion. Include what happens in each reaction, the types of atoms involved, the

types of products produced, and the practical uses and limitations of each type of reaction.
Chemistry
1 answer:
earnstyle [38]3 years ago
3 0
Answer 1) What is nuclear fission and nuclear fusion? 
Nuclear Fission - It is reaction process when a neutron is made to strike to an atom with a heavy nucleus. It makes the atom release certain number of neutrons from the nucleus, then it splits the parent atom into smaller other atoms.

Nuclear Fusion - It is exactly opposite of nuclear fission. It is a reaction process, where the nucleus of certain light atoms tries to join the nucleus of other lighter atoms together and release large amount of energy.

Answer  2) What happens in these reactions?
 Nuclear Fission -  Usually in these reactions the atoms with heavy nucleus splits up into smaller atoms. Fission means breaking into smaller atoms.

Nuclear Fusion - In this reaction the atoms of several lighter nucleus combines together to form a larger nucleus by releasing a high amount of energy. Fusion means joining/mixing of small atoms to form large atom.

Answer 3) Types of atoms involved?
Nuclear Fission -  Atoms with heavy nucleus like uranium which when bombarded with neutrons can get splitted into smaller atoms of xenon or strontium,etc.

Nuclear Fusion - Atoms including small lighter nucleus combines to form larger  ones. For example, inside the Sun, the small atoms of hydrogen combines to form helium atoms which imparts sun a large amount of heat and light energy.

Answer 4) Types of product produced?
Nuclear Fission - Depending upon the atoms of heavy nucleus undergoing fission the products would be produced. Such as if uranium undergoes fission the products obtained will be different than Plutonium undergoing fission. Although several small by products may be similar.

Nuclear Fusion - This reaction also depending upon the smaller atoms nucleus which undergoes the process of fusion and result into a bigger atom. Example is the fusion of hydrogen atoms in sun and stars.

Answer 5) Practical Uses.
Nuclear Fission - As in this process large amount of energy is released, the major use is done in producing power. Also it's uses are seen in manufacturing of nuclear weapons.

Nuclear Fusion - It is difficult to do fusion reactions, but still we have managed to manufacture hydrogen bombs using this reaction and many researches are going on in the field of magnetism and laser beams.

Answer 6) Limitations.

Nuclear Fission -  The major limitation in using this kind of reaction is because of the generation of radioactive wastes. It is difficult to dispose off the waste generated after the reaction with proper care. It effect remains years after years and are extremely toxic to all living beings.

Nuclear Fusion - It is quite difficult to nuclear fusion reaction on earth as it requires high amount of temperature and pressure. So it is almost impossible to replicate fusion reactions.
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This coffee pot has a temperature of 23 degrees. The coffee cup was put in the microwave and is now 45 degrees. Which one has a
qwelly [4]

Answer:

. Which one has a greater thermal energy?

the coffee cup

8 0
2 years ago
A 42.0g sample of a compound containing only C and H was analyzed. The results showed that the sample contained 36.0g of C and 6
SashulF [63]

Answer:

The correct answer is option D.

Explanation:

Mass of compound = 42.0 g

Mass of carbon in compound = 36.0 g

Mass of hydrogen in compound = 6.0 g

Moles of carbon = \frac{36.0 g}{12 g/mol}=3.0 mol

Moles of hydrogen = \frac{6.0 g}{1 g/mol}=6.0 mol

Empirical formula of the compound, divide least number of moles from each element.

Carbon = \frac{3.0}{3.0}=1

Hydrogen = \frac{6.0}{3.0}=2

Empirical formula of compound = CH_2

The empirical formula of the compound can be calculated from the given data.

4 0
2 years ago
The total daily water use in Mexico is 88 billion m ^ 3 the Mexican population is 127.5 million people. What is the per capita d
eimsori [14]

This problem is providing the water consumption in Mexico as 88 billion m³ and the Mexican population as 127.5 million people so that the per capita daily water use is required and found to be 690 m³/person according to the following:

<h3>Dimensional analysis:</h3><h3 />

In chemistry, the use of dimensional analysis and units conversion covers a wide range of calculations, necessary to report a result in a specific way. In this case, we see this problem asks for the consumption of water, in cubic meters, that each person does every day.

Thus, with a view to calculating this, one must first write this values without any million or billion system as shown below:

88billion\ m^3=88.000.000.000 m^3 =8.8x10^{10}m^3\\\\127.5million\ people=127.500.000 people=1.275x10^8people

This means we can get the per capita daily water use by simply dividing these two:

\frac{8.8x10^{10}m^3}{1.275x10^8people}\\\\= 690\frac{m^3}{person}

Learn more about dimensional analysis: brainly.com/question/10874167

8 0
2 years ago
What causes a change in a state of matter? Help please
pickupchik [31]

Answer:

Going through a phase. Adding or removing energy from matter causes a physical change as matter moves from one state to another. For example, adding thermal energy (heat) to liquid water causes it to become steam or vapor (a gas). Physical changes can also be caused by motion and pressure.

Explanation:

Hope this helps :)

7 0
2 years ago
Just enough 0.500 M HCl is added to 30.0 mL of 2.5 M NH3 to reach the equivalence point. The Kb of NH3 = 1.8 X 10-5
algol13

a.NH₃+HCl⇒NH₄Cl

b.volume HCl=150 ml

c. pH=4.82

<h3>Further explanation</h3>

Reaction

NH₃+HCl⇒NH₄Cl

The equivalence point⇒mol NH₃=HCl

Titration formula :

M₁V₁n₁=M₂V₂n₂(n=acid base valence, NH₃=HCl=1)

mol NH₃

\tt 2.5\times 30=75~mlmol

mol HCl=75 mlmol

  • Volume HCl :

\tt \dfrac{75}{0.5}=150~ml

Volume total :

\tt 150+30=180~ml

  • molarity of salt(NH₄Cl)

mol NH₄Cl=mol NH₃=75 mlmol=0.075 mol

\tt M=\dfrac{0.075}{0.180}= 0.42

  • pH of solution

Dissociation of NH₄Cl at water to find [H₃O⁺]

\tt NH_4+H_2O\rightarrow NH_3+H_3O^+

ICE at equilibrium :

0.41-x            x        x

Ka(Kw:Kb)= 10⁻¹⁴ : 1.8.10⁻⁵=5.6.10⁻¹⁰

\tt Ka=\dfrac{NH_3.H_3O}{NH_4}=\dfrac{x^2}{0.41}

[H₃O⁺]=x :

\tt \sqrt{5.6.10^{-10}\times 0.41}=1.515.10^{-5}

pH=-log[H₃O⁺]

\tt pH=5-log~1.515=4.82

7 0
3 years ago
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