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4 years ago

An 820 N Marine in basic training climbs a 12.0-m vertical rope at a constant speed in 8.00 s. What is her power output

Physics

1 answer:

sweet-ann [11.9K]4 years ago

6 0

Answer:

1230 W

Explanation:

P = $\frac{W}{t}$ = $\frac{Force * distance}{time}$ = $\frac{820 N * 12.0 m}{8.00 s}$ = 1230 Watts

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Please help with these physics problems 1. A soccer ball is dropped from the top of a building. It takes 5.8 seconds to fall to

Tatiana [17]

Answer:

1.) h = 164.8 m

2.) U = 49.1 m/s

3.) t = 1.43 seconds

Explanation:

1.) A soccer ball is dropped from the top of a building. It takes 5.8 seconds to fall to the ground. The height of the building is...?

Since the soccer ball is dropped from the building, the initial velocity U will be equal to zero

Using second equation of motion

h = Ut + 1/2gt^2

Substitutes the time into the formula

h = 1/2 × 9.8 × 5.8^2

h = 164.8 m

2. The Falcon 9 launches to a height of 123 meters. What is its vertical initial velocity?

At maximum height final velocity = 0

Using the third law of motion

V^2 = U^2 - 2gH

0 = U^2 - 2 × 9.8 × 123

U^2 = 2410.8

U = 49.1 m/s

3. An apple falls from rest off a 10.m m tree. How long will it take before it hits the ground?

Since the apple fall from rest, the initial velocity U will be equal to zero

Using the second equation of motion,

h = Ut + 1/2gt^2

substitute all the parameters into the formula

10 = 1/2 × 9.8 × t^2

10 = 4.9t^2

t^2 = 10/4.9

t^2 = 2.04

t = 1.43 seconds

8 0

4 years ago

*NEED ANSWER STAT*

tresset_1 [31]

Becomes a +1 ion for this

6 0

3 years ago

Read 2 more answers

Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approxim

Schach [20]

Complete Question

Suppose a NASCAR race car rounds one end of the Martinsville Speedway. This end of the track is a turn with a radius of approximately 57.0 m . If the track is completely flat and the race car is traveling at a constant 30.5 m/s (about 68 mph ) around the turn.

Required:

a. What is the race car's centripetal (radial) acceleration?

b. What is the force responsible for the centripetal acceleration in this case?

O normal

O gravity

O friction

O weight

Answer:

question a

$a = 16.32 \ m/s^2$

question b

correct option is option 3

Explanation:

From the question we are told that

The radius is $r = 57.0 \ m \$

The constant speed at which the race car is travelling is $v = 30 .5 \ m/s$

Generally from the question we are told that the track is completely flat so the only force pulling the car to the middle is the frictional force hence the centripetal force is due to the frictional force

Generally the centripetal acceleration is mathematically represented as

$a = \frac{v^2}{r}$