Answer:
Explanation:
We shall apply the formula for velocity in case of elastic collision which is given below
v₁ = (m₁ - m₂)u₁ / (m₁ + m₂) + 2m₂u₂ / (m₁ + m₂)
m₁ and u₁ is mass and velocity of first object , m₂ and u₂ is mass and velocity of second object before collision and v₁ is velocity of first velocity after collision.
Here u₁ = 22 cm /s , u₂ = - 14 cm /s . m₁ = 7.7 gm , m₂ = 18 gm
v₁ = ( 7.7 - 18 ) x 22 / ( 7.7 + 18 ) + 2 x 18 x - 14 / ( 7.7 + 18 )
= - 8.817 - 19.6
= - 28.4 cm / s
To solve this problem we will apply the concepts related to load balancing. We will begin by defining what charges are acting inside and which charges are placed outside.
PART A)
The charge of the conducting shell is distributed only on its external surface. The point charge induces a negative charge on the inner surface of the conducting shell:
. This is the total charge on the inner surface of the conducting shell.
PART B)
The positive charge (of the same value) on the external surface of the conducting shell is:
The driver's net load is distributed through its outer surface. When inducing the new load, the total external load will be given by,
Explanation:
Two objects that only have the force of gravity acting on them, will fall with the same acceleration <span>g=9.8<span>m<span>s2</span></span>; g=32.2<span><span>ft</span><span>s2</span></span></span> and will therefore hit the ground at the same time.
When you drop a feather, air resistance acts on all the surfaces of the feather. This causes the feather to slow down.
Air resistance depends on two factors: the speed of the object (increased for example by throwing it), and its surface area.
hope this can give u a little bet more to know about how to get ur answer :P
have a gud day and gud luck!