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3 years ago

Chris has a bag of sweets. there are more than 20 sweets in a bag.

Mathematics

2 answers:

MA_775_DIABLO [31]3 years ago

7 0

No he is not correct

kiruha [24]3 years ago

4 0

The answer is no because if it is over 20 but he shared is equally with 6 people then it stands to reason that the amount was exactly 24 which isnt a prime number

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This is due tomorrow and i have answers but i think ive done it wrong! please help

Eva8 [605]

Answer: i) 1 - 9x² - 12x

ii) 17 - 3x²

iii) - 20 + 10x² - x⁴

Step-by-step explanation:

g(x) = 3x + 2 h(x) = 5 - x²

i) h(g(x))

h(3x + 2) = 5 - (3x + 2)²

= 5 - (9x² + 12x + 4)

= 5 - 9x² - 12x - 4

= 1 - 9x² - 12x

ii) g(h(x))

g(5 - x²) = 3(5 - x²) + 2

= 15 - 3x² + 2

= 17 - 3x²

iii) h(h(x))

h(5 - x²) = 5 - (5 - x²)²

= 5 - (25 - 10x² + x⁴)

= 5 - 25 + 10x² - x⁴

= -20 + 10x² - x⁴

4 0

3 years ago

HURRY PLEASE I NEED IT ASAP 15 POINTSS!!!!

expeople1 [14]

D shows equivalent expressions

3 0

2 years ago

Read 2 more answers

For tall heterozygotes with antennae, the offspring are:

Misha Larkins [42]

Recombinant frequency between T and A is 12%

Explanation:

Two characters are considered - height and antennae

Traits of height - Tall and Dwarf

Traits of antennae - Antennae and No antennae

Given:

Tall-antennae (46) and dwarf-no antennae (42) are the wild type.

Dwarf- antennae (7) and tall- no antennae (5) are the recombinants.

Total possibilities = 100

Recombinant frequency = $\frac{7}{100} + \frac{5}{100}$

Recombinant frequency = $\frac{12}{100}$

Recombinant frequency in percentage = $\frac{12}{100} X 100 = 12$ %

Therefore, recombinant frequency between T and A is 12%

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2 years ago

PLEASE HELPPP!!!?!?? I REALLY NEED IT!!!

DIA [1.3K]

All of the above is the correct answer

4 0

2 years ago

Read 2 more answers

Please help me i need to find the area of shaded region please help me

Montano1993 [528]

Answer:

Part 1) $A=60\ ft^2$

Part 2) $A=80\ cm^2$

Part 3) $A=96\ m^2$

Part 4) $A=144\ cm^2$

Part 5) $A=13\ m^2$

Part 6) $A=(49\pi -33)\ in^2$

Step-by-step explanation:

Part 1) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior rectangle

The area of rectangle is equal to

$A=bh$

where

b is the base of rectangle

h is the height of rectangle

$A=(12)(7)-(8)(3)\\A=84-24\\A=60\ ft^2$

Part 2) we know that

The shaded region is equal to the area of the complete rectangle minus the area of the interior square

The area of square is equal to

$A=b^2$

where

b is the length side of the square

$A=(12)(8)-(4^2)\\A=96-16\\A=80\ cm^2$

Part 3) we know that

The area of the shaded region is equal to the area of four rectangles plus the area of one square

$A=4(4)(5)+(4^2)\\A=80+16\\A=96\ m^2$

Part 4) we know that

The shaded region is equal to the area of the complete square minus the area of the interior square

$A=(15^2)-(9^2)\\A=225-81\\A=144\ cm^2$

Part 5) we know that

The area of the shaded region is equal to the area of triangle minus the area of rectangle

The area of triangle is equal to

$A=\frac{1}{2}(b)(h)$

where

b is the base of triangle

h is the height of triangle

$A=\frac{1}{2}(6)(7)-(4)(2)\\A=21-8\\A=13\ m^2$

Part 6) we know that

The area of the shaded region is equal to the area of the circle minus the area of rectangle

The area of the circle is equal to

$A=\pi r^{2}$

where

r is the radius of the circle

$A=\pi (7^2)-(3)(11)\\A=(49\pi -33)\ in^2$

6 0

3 years ago