d.
Because a <em>complete</em> ionic equation wants you to show everything participating in the reaction. Even if some are spectator ions that do not affect the final equation you still must include them and therefore c. could not be the answer.
The Orbital configuration for Manganese is as follows:
1s2 2s2 2p6 3s2 3p6 4s2 3d5
It says 3d is shown with five orbitals- this is correct
Then it says the first two orbitals have two electrons-this is incorrect.
When filling in the orbitals for any element, you first need to distribute to ALL orbitals then extras go from there.
The orbital d can have up to 10 electrons so you need to distribute at least one electron to all ten. Since you only have 5 then only 5 orbitals would have electrons in them. In order for ANY of the orbitals to have two electrons, there would need to be AT LEAST 11 electrons to distribute.
Answer:
0.133 M
Explanation:
The volume of the solution is given, so in order to find concentration, the number of moles must be found, since C = n/V.
The balanced reaction equation is:
HI + KOH ⇒ H₂O + KI
Thus, the moles of KOH added to neutralize all of the HI will be equal to the moles of HI that must have been present.
The amount of KOH that was added is calculated as follows.
n = CV = (0.145 mol/L)(45.7 mL) = 6.6265 mmol KOH = 6.6265 mmol HI
Since HI and KOH are related in a 1:1 molar ratio, the same amount of HI must have been present.
Finally, the concentration of HI is calculated:
C = n/V = (6.6265 mmol) / (50.0 mL) = 0.133 mol/L = 0.133 M
The answer is D. compare the pH paper's color with a chart of colors and pH ranges. This is the method of using pH paper. pH paper is just a method to determine the pH number roughly.
