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2 years ago

How many electrons are lost or gained in forming each ion? a. Ba2+ b. As3- c. Cu2+

Chemistry

2 answers:

vovangra [49]2 years ago

6 0

Answer:

See below

Explanation:

Part a)

Ba⁺²

Since it has a positive charge, this means it has lost electrons and that too 2 electrons. It has lost 2 electrons.

Part b)

As⁻³

Since it has a negative charge, it has gained electrons and that too 3 electrons. It has gained 3 electrons.

Part c)

Cu⁺²

It has a positive charge, so it has lost electrons and that too 2 electrons. It has lost 2 electrons.

$\rule[225]{225}{2}$

astra-53 [7]2 years ago

3 0

B. As3 because potassium atoms do this to form ions with the same electron configuration as the noble gas argon

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3 years ago

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3 years ago

I have 2 samples of solid chalk (aka calcium carbonate). Sample A has a total mass of 4.12 g and Sample B has a total mass of 19

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Answer:

A) Sample B has more calcium carbonate molecules

Explanation:

M = Molar mass of calcium carbonate = 100.0869 g/mol

$N_A$ = Avogadro's number = $6.022\times 10^{23}\ \text{mol}^{-1}$

For the 4.12 g sample

Moles of a substance is given by

$n=\dfrac{m}{M}\\\Rightarrow n=\dfrac{4.12}{100.0869}\\\Rightarrow n=0.0411\ \text{mol}$

Number of molecules is given by

$nN_A=0.0411\times 6.022\times 10^{23}=2.48\times 10^{22}\ \text{molecules}$

For the 19.37 g sample

$n=\dfrac{19.37}{100.0869}\\\Rightarrow n=0.193\ \text{mol}$

Number of molecules is given by

$nN_A=0.193\times 6.022\times 10^{23}=1.16\times 10^{23}\ \text{molecules}$

$1.16\times 10^{23}\ \text{molecules}>2.48\times 10^{22}\ \text{molecules}$

So, sample B has more calcium carbonate molecules.

The ratio of the elements of carbon, oxygen, calcium atoms, ions, has to be same in both the samples otherwise the samples cannot be considered as calcium carbonate. Same is applicable for impurities. If there are impurites then the sample cannot be considered as calcium carbonate.

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