Which molecule is an alkene?

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TiliK225 [7]

1. Increases
2. Decreases
3. Increases
4. Decreases
5. Decreases
6. Increases

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7 0

3 years ago

Combine the two half-reactions that give the spontaneous cell reaction with the smallest E∘. Fe2+(aq)+2e−→Fe(s) E∘=−0.45V I2(s)+

Iteru [2.4K]

Answer: The spontaneous cell reaction having smallest $E^o$ is $I_2+Cu\rightarrow Cu^{2+}+2I^-$

Explanation:

We are given:

$E^o_{(Fe^{2+}/Fe)}=-0.45V\\E^o_{(I_2/I^-)}=0.54V\\E^o_{(Cu^{2+}/Cu)}=0.34V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, iodine will always undergo reduction reaction, then copper and then iron.

The equation used to calculate electrode potential of the cell is:

$E^o_{cell}=E^o_{oxidation}+E^o_{reduction}$

The combination of the cell reactions follows:

Case 1:

Here, iodine is getting reduced and iron is getting oxidized.

The cell equation follows:

$I_2(s)+Fe(s)\rightarrow Fe^{2+}(aq.)+2I^-(aq.)$

Oxidation half reaction: $Fe(s)\rightarrow Fe^{2+}(aq.)+2e^-$ $E^o_{oxidation}=0.45V$

Reduction half reaction: $I_2(s)+2e^-\rightarrow 2I_-(aq.)$ $E^o_{reduction}=0.54V$

$E^o_{cell}=0.45+0.54=0.99V$

Thus, this cell will not give the spontaneous cell reaction with smallest $E^o_{cell}$

Case 2:

Here, iodine is getting reduced and copper is getting oxidized.

The cell equation follows:

$I_2(s)+Cu(s)\rightarrow Cu^{2+}(aq.)+2I^-(aq.)$

Oxidation half reaction: $Cu(s)\rightarrow Cu^{2+}(aq.)+2e^-$ $E^o_{oxidation}=-0.34V$

Reduction half reaction: $I_2(s)+2e^-\rightarrow 2I_-(aq.)$ $E^o_{reduction}=0.54V$

$E^o_{cell}=-0.34+0.54=0.20V$

Thus, this cell will give the spontaneous cell reaction with smallest $E^o_{cell}$

Case 3:

Here, copper is getting reduced and iron is getting oxidized.

The cell equation follows:

$Cu^{2+}(aq.)+Fe(s)\rightarrow Fe^{2+}(aq.)+Cu(s)$

Oxidation half reaction: $Fe(s)\rightarrow Fe^{2+}(aq.)+2e^-$ $E^o_{oxidation}=0.45V$

Reduction half reaction: $Cu^{2+}(aq.)+2e^-\rightarrow Cu(s)$ $E^o_{reduction}=0.34V$

$E^o_{cell}=0.45+0.34=0.79V$

Thus, this cell will not give the spontaneous cell reaction with smallest $E^o_{cell}$

Hence, the spontaneous cell reaction having smallest $E^o$ is $I_2+Cu\rightarrow Cu^{2+}+2I^-$

7 0

3 years ago

Will combining water and baking soda make a chemical reaction?

Mashcka [7]

Answer:

The baking powder reacts with water to produce bubbles, while baking soda does not react with water.

Explanation:

8 0

3 years ago

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One container is filled with argon gas and the other with krypton gas. If both gases have the same temperature, in which contain

alina1380 [7]

Answer:

Argon

Explanation:

The average kinetic energy of the particles in a gas is given by

$KE=\frac{1}{2}mv^2$

where

m is the mass of the particles

v is their rms speed

The average kinetic energy of the particles in a gas can also be written as

$KE=\frac{3}{2}kT$

where

k is the Boltzmann's constant

T is the absolute temperature of the gas

Combining the two equations,

$\frac{1}{2}mv^2=\frac{3}{2}kT$

We can re-write the equation as

$v=\sqrt{\frac{3kT}{m}}$

We see that:

- The speed is directly proportional to the square root of the temperature

- The speed is inversely proportional to the square root of the mass of the particles

Therefore, if the two gases are at same temperature, the particles will move faster in the gas with lighter particles (smaller mass).

Since Krypton atoms have larger mass than Argon atoms, it means that atoms in Argon move faster than in Krypton.

7 0

3 years ago

a habitat must include all of the following except a. food sources. b. favorable conditions for reproduction. c. more than one p

I am Lyosha [343]

A habitat must include all of the following except C. More than one population of a given species.

3 0

3 years ago

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