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Kaylis [27]
3 years ago
15

An arctic weather balloon is filled with 38.5 L of helium gas inside a prep shed. The temperature inside the shed is 8. °C. The

balloon is then taken outside, where the temperature is -41. °C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.
Chemistry
1 answer:
Naily [24]3 years ago
3 0

Answer: The new volume of the balloon is 197.31 L.

Explanation:

Given: V_{1} = 38.5 L,        T_{1} = 8^{o}C

V_{2} = ?,                     T_{2} = 41^{o}C

According to Charles law, at constant pressure the volume of a gas is directly proportional to temperature.

Formula used to calculate the new volume is as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}\\\frac{38.5 L}{8^{o}C} = \frac{V_{2}}{41^{o}C}\\V_{2} = \frac{38.5 L \times 41^{o}C}{8^{o}C}\\= 197.31 L

Thus, we can conclude that the new volume of the balloon is 197.31 L.

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Answer:

The mass of sodium metal that must be introduced to water to produce 3.3 grams of hydrogen gas, H₂, is approximately 18.82 grams of sodium metal

Explanation:

The given mass of hydrogen gas produced = 3.3 grams

The molar mass of hydrogen gas, H₂ = 2.016 g/mol

The number of moles of hydrogen gas in 3.3 grams of H₂, 'n', is given as follows;

n = Mass/(Molar mass)

n = 3.3 g/(2.016 g/mol) = 1.63690476 moles of H₂

The reaction of sodium and water can be written as follows;

2Na + 2H₂O → 2NaOH + H₂ (g)

2 moles of sodium produces 1 mole of hydrogen gas, H₂

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1.63690476/2 moles of sodium will produce 1.63690476 moles of hydrogen gas, H₂

The molar mass of sodium, Na ≈ 22.989 g/mol

The mass of 1.63690476/2 moles of sodium, 'm', is given as follows;

m = 1.63690476/2 moles × 22.989 g/mol ≈ 18.8154018 grams ≈ 18.82 grams

The mass of sodium that will produce 3.3 grams of hydrogen, m ≈ 18.82 grams of sodium metal.

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3 years ago
What is the oxidation state of S in HSO4^2-? (A.P.E.X)
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I think there is a typo because I've never seen HSO4 2- before in my life. It should be HSO4-. For that, H is 1+ and each Oxygen is 2-0 totaling 8-. So the oxidation state of sulfur +1 - 8 = 7

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