Answer:
The mass of sodium metal that must be introduced to water to produce 3.3 grams of hydrogen gas, H₂, is approximately 18.82 grams of sodium metal
Explanation:
The given mass of hydrogen gas produced = 3.3 grams
The molar mass of hydrogen gas, H₂ = 2.016 g/mol
The number of moles of hydrogen gas in 3.3 grams of H₂, 'n', is given as follows;
n = Mass/(Molar mass)
n = 3.3 g/(2.016 g/mol) = 1.63690476 moles of H₂
The reaction of sodium and water can be written as follows;
2Na + 2H₂O → 2NaOH + H₂ (g)
2 moles of sodium produces 1 mole of hydrogen gas, H₂
Therefore;
1.63690476/2 moles of sodium will produce 1.63690476 moles of hydrogen gas, H₂
The molar mass of sodium, Na ≈ 22.989 g/mol
The mass of 1.63690476/2 moles of sodium, 'm', is given as follows;
m = 1.63690476/2 moles × 22.989 g/mol ≈ 18.8154018 grams ≈ 18.82 grams
The mass of sodium that will produce 3.3 grams of hydrogen, m ≈ 18.82 grams of sodium metal.
 
        
             
        
        
        
I think there is a typo because I've never seen HSO4 2- before in my life. It should be HSO4-. For that, H is 1+ and each Oxygen is 2-0 totaling 8-. So the oxidation state of sulfur +1 - 8 = 7 
So the oxidation state of sulfur is +6
 
        
             
        
        
        
Answer:
Both sodium and calcium.
Explanation:
The membrane potential is maintained inside and outside of the cell due to the unequal distribution of the different ions. This membrane potential difference is important for the generation of action potential.
The resting membrane potential is around +30 mV. This is due to the presence of potassium ions. The sodium and calcium ions must enter in the cell to change this membrane potential and generates the action potential in the body. 
Thus, the correct answer is option (3).
 
        
             
        
        
        
Answer:
im pretty sure the correct option here id c
can i please get brainliest
 
        
             
        
        
        
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