Answer:
i think you have to measure your diagram with a protector to find the angles
Given:
The function are


To find:
The value of
.
Solution:
We have,


We need to find the value of
.
![[\because (f\circ g)(x)=f(g(x))]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28f%5Ccirc%20g%29%28x%29%3Df%28g%28x%29%29%5D)
![[\because g(x)=\sqrt{x}]](https://tex.z-dn.net/?f=%5B%5Cbecause%20g%28x%29%3D%5Csqrt%7Bx%7D%5D)
![[\because f(x)=x^2-1]](https://tex.z-dn.net/?f=%5B%5Cbecause%20f%28x%29%3Dx%5E2-1%5D)
The value of
is 0.
Therefore, the correct option is A.
Answer:
For number 2, its A. For number 1, its C.
Step-by-step explanation:
For both equations, you just set it equal to to each other because alternate interior angles are equivalent.
2) The equation would be
7x+3=6x+12
Then solve.
1) The equation would be
14x-3=95
Then solve.
I love geometry! If you have questions, just comment.
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PLEASE MARK BRAINLIEST!</u></h2>
Answer:
- Is y = 4x - 7 a linear function?
- Is y = 6x² - 1 a linear function?
- Is y =
+ 10 a linear function?
Step-by-step explanation:
- Yes it is - when you graph this equation, it results in a [straight] line, signalling that it is a linear function.
- No it's not - when you graph this equation, it results in a v- kinda shape on the graph. Linear functions are [straight] lines on a graph, and this line wasn't straight. In fact, this wasn't even a line.
- No it's not - when you graph this equation, it results in a bend at the origin. The line on the graph is not straight, so this is not a linear equation.
For the graphs -
- The first one represents the linear function [y = 4x - 7]
- The second one (that looks like an L) represents the last not linear function [y =
+ 10]
- The third one (that looks like a V) represents the first not linear function [y = 6x² - 1]
I HOPE THIS HELPS!
Answer:
Garrett can order stickers from two companies. Company A charges a $30 design fee plus $0.80 per sticker. Company B charges a $14 design fee plus $1.20 per sticker. How many stickers would Garrett have to order for the cost at both companies to be the same?
Step-by-step explanation:
i got it right