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Mumz [18]
3 years ago
9

How many kilojoules are associated with the formation of 2 moles of HBr(g)

Chemistry
2 answers:
Lady bird [3.3K]3 years ago
4 0
HBr is formed from hydrogen gas and bromine gas as shown in the reaction below;
            H2(g) + Br2(g) = 2HBr(g)       
The reaction involves bond breaking and bond formation
Decomposition of 1 mole of HBr requires 36.4kj/mol,
But, energy used in decomposition = energy used in formation
Thus,  formation of a mole of HBr is -36.4 kj/mol
Therefore, formation of two moles of HBr would require
   (-36.4 ×2) = 72.8

≈ -73 kj/mol
Hence, the enthalpy of formation of 2 moles of HBr (ΔH) is -73 kj/mol
nexus9112 [7]3 years ago
4 0

  (-36.4 ×2) = 72.8


≈ -73 kj/mol

Hence, the enthalpy of formation of 2 moles of HBr (ΔH) is -73 kj/mol

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The question is incomplete, the complete question is;

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