<span>0.333 ounce * 0.75 * 28.35 grams/ounce = 7.080 grams gold
7.080 grams Au / 196.967g/mol Au = 0.0359 mol Au
0.0359 mol Au * (6.023 * 10^23) atoms/mol = 2.24 * 10^22 Atoms Au</span>
Answer:
Average atomic mass = 55.83 amu
Explanation:
The formula for the calculation of the average atomic mass is:
Given that:
For first isotope, Fe-54:
% = 6 %
Mass = 53.94 amu
For second isotope, Fe-56:
% = 92 %
Mass = 55.93 amu
For third isotope, Fe-57:
% = 2 %
Mass = 56.94 amu
Thus,
<u>Average atomic mass = 55.83 amu</u>
Answer:
electron configuration
Explanation:
The arrangement of electrons in the atomic orbitals of an atom is called the electron configuration. Electron configurations can be determined using a periodic table.
Gallum: Z = 31
electron configuration: [Ar] 4s^2 3d10 4s2 4p1
Highest energy electron: 4p1
Quantum numbers:
n = 4, because it is the shell number
l = 1, it corresponds to type p orbital
ml = may be -1, or 0, or +1, depending on space orientation, they correspond to px, py, pz
ms = may be -1/2 or +1/2, this is the spin number.
Answer:
30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.
Explanation:
Let volume of the 40% acid solution be x.
Let volume of the 60% acid solution be y.
Volume of solution formed after mixing both solution = 40 L
x + y = 40 L..[1]
Volume of acid 40% solution = 40% of x= 0.4x
Volume of acid 60% solution = 60% of y= 0.6y
Volume of acid formed = 45% of 40 L = 
..[2]
Solving [1] and [2]
x = 30 L , y = 10 L
30 Liters of 40% acid solution and 10 L of 60% acid solution is needed.