Location = nucleus ,
and you can see the total charge on the number that written below the substance, which would be 28+
hope this helps
Answer:
molecular weight (Mb) = 0.42 g/mol
Explanation:
mass sample (solute) (wb) = 58.125 g
mass sln = 750.0 g = mass solute + mass solvent
∴ solute (b) unknown nonelectrolyte compound
∴ solvent (a): water
⇒ mb = mol solute/Kg solvent (nb/wa)
boiling point:
- ΔT = K*mb = 100.220°C ≅ 373.22 K
∴ K water = 1.86 K.Kg/mol
⇒ Mb = ? (molecular weight) (wb/nb)
⇒ mb = ΔT / K
⇒ mb = (373.22 K) / (1.86 K.Kg/mol)
⇒ mb = 200.656 mol/Kg
∴ mass solvent = 750.0 g - 58.125 g = 691.875 g = 0.692 Kg
moles solute:
⇒ nb = (200.656 mol/Kg)*(0.692 Kg) = 138.83 mol solute
molecular weight:
⇒ Mb = (58.125 g)/(138.83 mol) = 0.42 g/mol
Answer:
There are
1.479
×
10
−
13
concentration of hydrogen ions
m
o
l
L
.
Explanation:
Because pH is a logarthmic scale, we can use the formula:
[
H
+
]
=
10
-pH
. Where...
=>
[
H
+
]
is the concentration of hydrogen ions in the solution.
=>
p
H
is the pH of the solution.
=> Where
10
is the base of the power - it's a logarithm formula.
We can now just sub in the values and solve for [
H
+
]
.
[
H
+
]
=
10
-pH
=
10
−
(
12.83
)
=
1.479108388
×
10
−
13
We can round (if required) to
1.479
×
10
−
13
.
Thus, there are
1.479
×
10
−
13
concentration of hydrogen ions
m
o
l
L
.
Hope this helps :)
