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BARSIC [14]
3 years ago
11

Interpret using 12 as a reference point how can you tell that the hands of the clock on the right have moved from the previous p

osition

Physics
1 answer:
zubka84 [21]3 years ago
6 0

Answer:

The answer is "6:45 and 7:15".

Explanation:

In the given attache file two clocks are added, that's explanation defined as follows:

In the left image, it may assume, that the clock only at the right-hand side of a scene is move-in its previous position, which is shown to the left, as it was at 6:45 on the left but in the right image it will display the time that is 7:15.

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Any help please, physics is not my strong suit?
frez [133]

Answer:

2000mg = 2g

5L = 5000mL

16cm = 160mm

5 0
3 years ago
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A spring suspended vertically is 11.9 cm long. When you suspend a 37 g weight from the spring, at rest, the spring is 21.5 cm lo
Naddika [18.5K]

Answer:

Time period of oscillations is 0.62 s

Explanation:

Due to suspension of weight the change in the length of the spring is given as

\Delta L = L_f - L_i

\Delta L = 21.5 - 11.9 = 9.6 cm

now we know that spring is stretched due to its weight so at equilibrium the force due to weight is counter balanced by the spring force

mg = kx

0.037 (9.81) = k(0.096)

k = 3.78 N/m

Now the period of oscillation of spring is given as

T = 2\pi \sqrt{\frac{m}{k}}

Now plug in all values in it

T = 2\pi \sqrt{\frac{0.037}{3.78}}

T = 0.62 s

5 0
3 years ago
If i try to fail and succeed which one did I do
Novay_Z [31]
You've failed because you failing becomes a statement rather than it becoming fact or what actually happened. 
7 0
3 years ago
Q.Solve the following circuit find total resistance RT. Also find value of voltage across resister RC.
vagabundo [1.1K]

Answer:

R_total = 14.57 Ω ,  V_C = 1.176 V

Explanation:

To solve this circuit we are going to find the equivalent resistance of each branch, let's remember

* Serial resistance  

         R_{eq} = ∑ R_{i}

* For resistance in parallel

        1 / R_{eq} = ∑ 1/R_{i}

We solve the two branches of the wheatstone bridge

Series resistors

Branch B

         R_B = Rb + R4

         R_B = 2 + 18

         R_B = 20 Ω

Branch C

         R_C5 = Rc + R5

         R_C5 = 3 + 12

         R_C5 = 15 Ω

Resistance in parallel R_B and R_C5

         1 / R_BC = 1 / R_B + 1 / R_C5

          1 / R_BC = 1/20 + 1/15 = 0.116666

          R_BC = 8.57 Ω

Now we have a single branch, we solve the series resistance

          R_total = R_A + R_BC

          R_total = 6 + 8.57

          R_total = 14.57 Ω

b) they ask us for the voltage in the resistance R_C

Let's remember that the voltage in a series circuit is the sum of the voltages

           10 = V_a + V_BC

           10 = i R_a + i R_BC = i (R_a + R_BC)

           i = 10 / (R_a + R_BC)

           i = 10 / (14.57)

           i = 0.6863 A

The current in the series circuit is constant

          V_BC = i R_BC

          V_BC = 0.6863 8.57

          V_BC = 5.8819 V

This voltage is divided in the bridge, for the two branches in parallel it is the same, but the resistance is different in each branch.

     Branch C

             V_BC = i R_C5

             i = V_BC / R_C5

             i = 5.8819 / 15

             i = 0.39213 A

In this branch we have two resistors in series, let's remember that the current in a series circuit is constant

             V_C = i R_C

              V_C = 0.39213 3

              V_C = 1.176 V

3 0
3 years ago
The length of the side of a cube is 10.0 ±0.3 cm. What is the absolute uncertainty in the perimeter of one side of the cube?
Nimfa-mama [501]

Answer:Stuff

Explanation: Nun

4 0
3 years ago
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