Answer:
g
Explanation:
if an object is thrown upward or at any angle, the acceleration acting on that object is the same as acceleration due to gravity which always acts towards the vertically downwards direction because there is no acceleration or the force acting on the object in horizontal direction.
Thus, the acceleration is same as acceleration due to gravity g.
Answer:
b. passes through the principal focal point.
Explanation:
Light wave can be defined as an electromagnetic wave that do not require a medium of propagation for it to travel through a vacuum of space where no particles exist.
A lens can be defined as a transparent optical instrument that refracts rays of light to produce a real image.
Basically, there are two (2) main types of lens and these includes;
I. Diverging (concave) lens.
II. Converging (convex) lens.
A converging lens refers to a type of lens that typically causes parallel rays of light with respect to its principal axis to come to a focus (converge) and form a real image. This type of lens is usually thin at the lower and upper edges and thick across the middle.
For a converging lens, a ray arriving parallel to the optic axis passes through the principal focal point.
Answer:
-5 V
Explanation:
The charged particle (which is positively charged) moves from point A to B, and its kinetic energy increases: it means that the particle is following the direction of the field, so its potential energy is decreasing (because it's been converted into potential energy), therefore it is moving from a point at higher potential (A) to a point at lower potential (B). This means that the value
vb−va
is negative.
We can calculate the potential difference between the two points by using the law of conservation of energy:
![\Delta K+ \Delta U=0\\\Delta K + q\Delta V=0](https://tex.z-dn.net/?f=%5CDelta%20K%2B%20%5CDelta%20U%3D0%5C%5C%5CDelta%20K%20%2B%20q%5CDelta%20V%3D0)
where:
is the change in kinetic energy of the particle
is the charge of the particle
is the potential difference
Re-arranging the equation, we can find the value of the potential difference:
![\Delta V=V_b-V_a = -\frac{\Delta K}{q}=-\frac{1.6\cdot 10^{-18} J}{3.2\cdot 10^{-19} C}=-5 V](https://tex.z-dn.net/?f=%5CDelta%20V%3DV_b-V_a%20%3D%20-%5Cfrac%7B%5CDelta%20K%7D%7Bq%7D%3D-%5Cfrac%7B1.6%5Ccdot%2010%5E%7B-18%7D%20J%7D%7B3.2%5Ccdot%2010%5E%7B-19%7D%20C%7D%3D-5%20V)
All of the electromagnetic energy radiated from the sun (and from
other stars) is the product of nuclear fusion in its core.