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sergij07 [2.7K]
3 years ago
13

Which statement best describes the difference between acceleration and deceleration?

Physics
1 answer:
natima [27]3 years ago
7 0
Acceleration is the rate at which an object picks up speed. deceleration is the rate at which an object loses speed.
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The amount of energy in a photon of light is proportional to the
blondinia [14]
The amount of energy of a photon is proportional to the frequency.
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3 years ago
Two mountain bikers are rolling down a hill. They both have the same mass, but one is taller and has more air drag (friction, et
svetlana [45]

Answer:The Taller one

Explanation: Air drag(friction) also known as air resistance,the opposing force acting against the force of gravity, if a falling Object have a high air drag it will mean the object have a high air resistance. The higher the air resistance the higher the impact of the force of gravity on an object. The force of gravity will act to want to overcome the opposing force in order to bring the Object or the taller person down.

4 0
4 years ago
In a hyrdo electic power plant the moving water turns the turbine creating ____________ energy.
Marrrta [24]

Answer:

....................

Explanation:

................

3 0
3 years ago
Read 2 more answers
if a tank filled with water contains a block and the height of the water above point A within the block is 0.6meter, what's the
Fittoniya [83]
The pressure exerted by a fluid solely relies on the depth or height of the fluid, its density, and the gravitational constant. These three are related in the equation:

Pressure = density x g x height

In the problem, point A is within the block inside the tank. The water above the block is assumed to be 0.6 meters. This gives a point A pressure of:

P = 1000 kg/m^3 * 9.81 m/s^2 * 0.6 m = 5,886 Pa or 5.88KPa
6 0
3 years ago
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What visible wavelengths of light are strongly reflected from a 390-nm-thick soap bubble?
DiKsa [7]

Answer:

So visible wavelength which is possible here is

416 nm and 693.3 nm

Explanation:

As we know that for normal incidence of light the path difference of the reflected ray is given as

2\mu t + \frac{\lambda}{2} = \Delta x

so here we can say that for maximum intensity condition we will have

\Delta x = N\lambda

so we have

2\mu t + \frac{\lambda}{2} = N\lambda

now for visible wavelength we have

for N = 1

2\mu t = \frac{\lambda}{2}

\lambda = 4\mu t

\lambda = 4(\frac{4}{3})(390 nm)

\lambda = 2080 nm

for N = 2

\lambda = \frac{4\mu t}{3}

\lambda = \frac{4(\frac{4}{3})(390 nm)}{3}

\lambda = 693.3 nm

for N = 3

\lambda = \frac{4\mu t}{5}

\lambda = \frac{4(\frac{4}{3})(390 nm)}{5}

\lambda = 416 nm

6 0
4 years ago
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