Answer:
(c) increase by a factor of four
Explanation:
the formular for the relationship between energy and current is E= I²Rt (Heat energy)
the heater is fairly independent of its temperature , and given the time to be constant.
with the current being doubled,
E = I² Rt
E/ I² = K
=
E2 = 
I2 = 2* I1
E2 = E1 * 4*I1² / I1²
dividing , we have that E2 = 4 * E1
which means during the same time interval the amount of energy will increase by a factor of four.
Answer:
70.9pi rad/s
Explanation:
angle turned through = 16
angular acceleration = 22.6 rad/s2
angular speed = 10.2 rad/s
time = ?
angular acceleration = angular speed/time
time = 10.2/22.6
time = <u>0</u><u>.</u><u>4</u><u>5</u><u> </u><u>s</u><u>e</u><u>c</u><u>o</u><u>n</u><u>d</u><u>s</u>
<u>angular speed</u><u> </u><u>=</u><u> </u><u>a</u><u>n</u><u>g</u><u>l</u><u>e</u><u> </u><u>t</u><u>u</u><u>r</u><u>n</u><u>e</u><u>d</u><u> </u><u>t</u><u>h</u><u>r</u><u>o</u><u>u</u><u>g</u><u>h</u><u>/</u><u>t</u><u>i</u><u>m</u><u>e</u>
<u>angular speed</u><u> </u><u>=</u> (16 × 2pi)/0.45
= 70.9pi rad/s
B. 24 ohms. D. Touch/hold feature
D. From negative to positive =negative charges
B. 24 ohms.
in parallel, combined resistance is less than the lowest resistance
Answer:
Explanation:
a ) It is given that bomb was at rest initially , so , its momentum before the explosion was zero.
b ) We shall apply law of conservation of momentum along x and y direction separately because no external force acts on the bomb.
If v be the velocity of the third part along a direction making angle θ
with x axis ,
x component of v = vcosθ
So momentum along x axis after explosion of third part = mv cosθ
= 10 v cosθ
Momentum along x of first part = - 5 x 42 m/s
momentum of second part along x direction =0
total momentum along x direction before explosion = total momentum along x direction after explosion
0 = - 5 x 42 + 10 v cosθ
v cosθ = 21
Similarly
total momentum along y direction before explosion = total momentum along y direction after explosion
0 = - 5 x 38 + 10 v sinθ
v sinθ= 21
squaring and and then adding the above equation
v² cos²θ +v² sin²θ = 21² +19²
v² = 441 + 361
v = 28.31 m/s
Tanθ = 21 / 19
θ = 48°