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viva [34]
3 years ago
7

A disk rolls along a flat surface at a constant speed of 10 m/s. Its diameter is 0.5 m. At a particular instant, point P on the

edge of the disk is 45°from the horizontal. What is the velocity of point P at that instant?
Physics
1 answer:
Irina18 [472]3 years ago
4 0

Answer:

Explanation:

Tangential velocity of point P ( v ) = 10 m/s making an angle of 45°from the horizontal due to rotation of disk.

Linear forward velocity due to linear forward motion of disc

= v = 10 m /s

Resultant velocity R

R²= 10² +10² + 2 . 10 . 10 cos 45

= 200 + 200 x .707

R = 18.47  m /s .

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Define the law of conservation of energy
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In physics, the law of conservation of energy<span> states that the total</span>energy<span> of an isolated system remains constant—it is said to be conserved over time. </span>Energy<span> can neither be created nor destroyed; rather, it transforms from one form to another.</span>
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Black smokers are hot volcanic vents that emit smoke deep in the ocean floor. Many of them teem with exotic creatures, and some
erica [24]

If the density of water does not vary and the vents range in depth from about 1500 m to 3200 m below the surface, then the gauge pressure at a 2452-m deep vent is 224.268 atm.

Calculation:

Step-1:

It is given that the vents range in depth from about 1500 m to 3200 m below the surface. If we are assuming that the density of water does not vary. Then it is required to calculate the gauge pressure at a 2452-m deep vent.

The gauge pressure at a particular depth of ocean water is calculated as:

$$P=\rho g h$$

Here \rho is the density of water, P is the required pressure, h is the depth of water, and g is the gravitational acceleration.

Step-2:

Now we are substituting the values to calculate the pressure at the depth of 2452-m.

$$\\\begin{aligned}\\P&=\rho gh\\&=1030 (\text{ kg/m}^3)\times 9.8 (\text{ m/s}^2)\times 2452 \text{ m}\\&=24.75\times 10^6 \text{ Pa}\times\frac{1 \text{ atm}}{10.1325 \times10^4 \text{ Pa}}\\&=224.268 \text{ atm}\\\end{aligned}\\$$

Learn more about gauge pressure here,

brainly.com/question/14012416

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5 0
2 years ago
Give two quantitative observation george might record
Over [174]
There are four chipmunks on that tree

two of the dogs have white fur
8 0
3 years ago
Find the momentum (in kg.m/s) of a helium nucleus having a mass of 6.68 x 10^-27 kg that is moving at 0.386c.
igomit [66]

Answer:

7.73544\times 10^{-21}kgm/sec

Explanation:

We have given mass of helium nucleus m=6.68\times 10^{-27}kg

Velocity of helium nucleus v=0.386c=0.386\times 3\times 10^{8}m/sec=1.158\times 10^{8}m/sec

Momentum of the helium nucleus is given by P=mv where m is mass and v is velocity

So P=mv=6.68\times 10^{-27}\times 1.158\times 10^{8}=7.73544\times 10^{-21}kgm/sec

6 0
3 years ago
For each question, select the right answer from the choices below:
Leni [432]

Option (ii) B is the correct option. The object on the moon has greater mass.

To resolve this, utilize the formulas Force = Mass * Acceleration.

The equation can be used to find the mass given the force in Newtons, using 9.8 m/s² for the acceleration of gravity of the earth and 1.6 m/s² for the moon.

Calculating the mass on earth:

30 N = 9.8 m/s² * mass

This results in a mass of 3.0 kg for the object on Earth.

Calculating the mass of the moon:

30 N = 1.6 m/s²2 * mass

Thus, the moon's object has a mass of 19. kg.

This can be explained by the fact that the earth has a stronger gravitational pull than the moon, producing more force per kilogram of mass. As a result, the moon's mass must be bigger to produce the same amount of force at a lower acceleration from gravity (1.6 m/s² vs. 9.8 m/s²).

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brainly.com/question/13386792

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3 0
1 year ago
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