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viva [34]
2 years ago
7

A disk rolls along a flat surface at a constant speed of 10 m/s. Its diameter is 0.5 m. At a particular instant, point P on the

edge of the disk is 45°from the horizontal. What is the velocity of point P at that instant?
Physics
1 answer:
Irina18 [472]2 years ago
4 0

Answer:

Explanation:

Tangential velocity of point P ( v ) = 10 m/s making an angle of 45°from the horizontal due to rotation of disk.

Linear forward velocity due to linear forward motion of disc

= v = 10 m /s

Resultant velocity R

R²= 10² +10² + 2 . 10 . 10 cos 45

= 200 + 200 x .707

R = 18.47  m /s .

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A block is attached to the end of a horizontal ideal spring and rests on a frictionless surface. The block is pulled so that the
bezimeni [28]

Answer:

The answer is "a, c and b"

Explanation:

  • Its total block power is equal to the amount of potential energy and kinetic energy.
  • Because the original block expansion in all situations will be the same, its potential power in all cases is the same.
  • Because the block in the first case has no initial speed, the block has zero film energy.
  • For both the second example, it also has the v_o velocity, but the kinetic energy is higher among the three because its potential and kinetic energy are higher.
  • While over the last case the kinetic speed is greater and lower than in the first case, the total energy is also higher than the first lower than that of the second.
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4 0
2 years ago
Density=2g/mL and volume=20mL what is mass
leva [86]

Answer:

40g

Explanation:

Mass = density x volume

= 2 x 20

= 40g

8 0
3 years ago
Read 2 more answers
A long wire carrying a 5.0 A current perpendicular to the xy-plane intersects the x-axis at x= - 2.0 cm . A second, parallel wir
mario62 [17]

Answer:

a . 0.35cm

b.  11.33cm

Explanation:

a. Given both currents are in the same direction, the null point lies in between them. Let x be distance of N from first wire, then distance from 2nd wire is 4-x

#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in between the wires:

\frac{\mu_oi_1}{2\pi x}=\frac{\mu_oi_2}{2\pi(4-x)}\\\\5/x=\frac{3.5}{4-x}\\\\x=2.35cm\\\\N=2.35-2=0.35cm

Hence, for currents in same direction, the point is 0.35cm

b. Given both currents flow in opposite directions, the null point lies on the other side.

#For the magnetic fields to be zero,the fields of both wires should be equal and opposite.They are only opposite in outside the wires:

Let x be distance of N from first wire, then distance from 2nd wire is 4+x:

\frac{\mu_oi_1}{2\pi(4+ x)}=\frac{\mu_oi_2}{2\pi x}\\\\5/(4+x)=\frac{3.5}{x}\\\\x=9.33cm\\\\N=9.33+2=11.33cm

Hence, if currents are in opposite directions the point on x-axis is 11.33cm

8 0
3 years ago
An astronaut lands on an alien planet. He places a pendulum (L = 0.200 m) on the surface and sets it in simple harmonic motion,
Ne4ueva [31]
A)  f = 1.8 rev/s = 2 Hz 
<span>T = 1 / f = 0.55s

B)  not really sure..srry

C)  </span><span>T = 2 pi √ ( L / g ) </span>
<span>0.57 = 2 x 3.14 x √ ( 0.2 / g )
</span><span>
g = 25.5 m/s²
</span>
Hope this helps a little at least.. :)

5 0
3 years ago
A good description of magnets would be, "Magnets are
madreJ [45]
B-things that can attract iron.
5 0
3 years ago
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