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Sergio039 [100]
3 years ago
10

I need help finding the solution

Physics
1 answer:
omeli [17]3 years ago
6 0

Answer:

objects with greater mass should have greater inertia

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A soccer ball is traveling at a velocity of 50 m/s. The kinetic energy of the ball is 500 J. What is the mass of the soccer ball
Savatey [412]
A soccer ball is traveling at a velocity of 50 m/s. The kinetic energy of the ball is 500 J.The mass of the soccer ball is 0.4 kgs. This answer is derived from the formula K=1/2 MV^2.So velocity and kinetic energy are given from that mass of the ball is calculated.By substituting the values 500=1/2*M*50*50 which gives M=0.4 Kgs.<span>
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4 0
3 years ago
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Which two fields of study do the principles of biomechanics come from? A. science and technology B. physics and engineering C. b
kati45 [8]

Answer:

B. physics and engineering

Explanation:

Biomechanics is the study of mechanical laws and living organisms. Hence, it comprises of the interrelationships between physics and engineering.

8 0
3 years ago
I need help with this problem :(​
Reil [10]

Answer:

it tells you that the speed increases until about 20 seconds then keeps a steady pace for 20 seconds then the speed drops and stops at 55 seconds in the process.

7 0
3 years ago
A barge floating in fresh water (p = 1000 kg/m3) is shaped like a hollow rectangular prism with base area A = 550 m2 and height H
Karolina [17]

Answer:

a) \Delta m = 330000\,kg, b) h = 1.268\,m

Explanation:

a) According the Archimedes' Principle, the buoyancy force is equal to the displaced weight of surrounding liquid. The mass of the coal in the barge is:

\Delta m \cdot g = \rho_{w}\cdot g \cdot \Delta V

\Delta m = \rho_{w}\cdot \Delta V

\Delta m = \left(1000\,\frac{kg}{m^{3}} \right)\cdot (550\,m^{2})\cdot (1.05\,m-0.45\,m)

\Delta m = 330000\,kg

b) The submersion height is found by using the equation derived previously:

\Delta m = \rho_{w}\cdot \Delta V

450000\,kg = \left(1000\,\frac{kg}{m^{3}}\right)\cdot (550\,m^{2})\cdot (h-0.45\,m)

The final submersion height is:

h = 1.268\,m

4 0
3 years ago
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A solid sphere of radius R carries a fixed, uniformly distributed charge q. Obtain an expression for the magnitude of the electr
NISA [10]

Answer:

The electric field outside the sphere will be \dfrac{qr}{4\pi\epsilon_{0}R^3}.

Explanation:

Given that,

Radius of solid sphere = R

Charge = q

According to figure,

Suppose r is the distance between the point P and center of sphere.

If \rho be the volume charge density,

Then, the charge will be,

q=\rho\times\dfrac{4}{3}\pi R^3.....(I)

Consider a Gaussian surface of radius r.

We need to calculate the electric field outside the sphere

Using formula of electric field

\oint{\vec{E}\cdot \vec{dA}}=\dfrac{Q}{\epsilon_{0}}

E\times4\pi r^2=\dfrac{\rho\dotc \dfrac{4}{3}\pi r^3}{\epsilon_{0}}

Put the value from equation (I)

E\times4\pi r^2=\dfrac{qr^3}{\epsilon_{0}R^3}

E=\dfrac{qr}{4\pi\epsilon_{0}R^3}

Hence, The electric field outside the sphere will be \dfrac{qr}{4\pi\epsilon_{0}R^3}.

4 0
3 years ago
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