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3 years ago

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A 12 oz can of soda is left in a car on a hot day. In the morning the soda temperature was 60oF with a gauge pressure of 40 psi.

What will the gauge pressure be when the soda reaches 90oF (or 363 Kelvin)?

1 answer:

Aneli [31]3 years ago

6 0

To answer this question, one must be familiar with Gay Lussac's Pressure Temperature Law. According to the law: $\frac{P1}{T1} = \frac{P2}{T2}$

Substituting the values:
Let x be the new gauge pressure.
$\frac{40}{60} = \frac{x}{90}$
We get x = 60psi.

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