Question

A 12 oz can of soda is left in a car on a hot day. In the morning the soda temperature was 60oF with a gauge pressure of 40 psi. What will the gauge pressure be when the soda reaches 90oF (or 363 Kelvin)?

Answer 1

To answer this question, one must be familiar with Gay Lussac's Pressure Temperature Law. According to the law:  $\frac{P1}{T1} = \frac{P2}{T2}$

Substituting the values: 
Let x be the new gauge pressure. 
$\frac{40}{60} = \frac{x}{90}$
We get x = 60psi.