W = m g weight of drop
W = q E
m = q E / g = = 3 e E / g
m = 3 * 1.6E-19 * 1.4E4 / 9.8 = 6.96E-16 kg
1. Acceleration
2. If you are going 12 meters per second and you want to know how many seconds it takes yo get to 105 meters, you need yo find how long it takes to go horizontally then vertically. 12 seconds.
3. B
Answer:571.09 kJ
Explanation:
Given
Temperature of cooling water from engine exit
After Passing through the radiator its temperature decreases to 
specific heat of water
Volume of water 
density of water 
Thus mass of water
Heat transferred to the surrounding is equal to heat absorbed by cooling water
Answer:
v2^2 - v1^2 = 2 g s fundamental formula
v2 = v1 + 2 g = v1 + 19.8 increase in velocity in 2 sec
v1^2 + 39.6 v1 + 392 - v1^2 = 2 * 9.8 * 123.1 = 2412.76
v1 = (2412.76 - 392) / 39.6 = 51.03
v2 = 51.03 + 19.6 = 70.63
T = 70.63 / .8 = 7.207 sec time to fall height of tower
S = 1/2 g T^2 = 4.9 * 7.207^2 = 254.5 m
(Note v2^2 - v1^2 = 70.63^2 - 51.03^2 = 2385 m
2385 / (2 * 9.8) = 122 m (close to 123.1 as was given
