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2 years ago

15 points. give me the method.

Physics

1 answer:

AveGali [126]2 years ago

5 0

Answer:

$\boxed{{160 \: m(s)}^{ - 1} }$

Explanation:

$if \:the \: frequencies \: are \to \\ f_{1} = 640Hz \\ and \\f_{2} = 480Hz \: \\ but \: \boxed{v = f \gamma }: f = \frac{v}{ \gamma } \\ if \: \gamma_{1} - \gamma _{2} = 1 = \gamma \\ f_{1} - f_{2} = 640 - 480 = \boxed{ 160Hz} = f \\ v = f \gamma = 160 \times 1 = \boxed{{160 \: m(s)}^{ - 1} }$

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How are surface temperature and length of year on a planet related to the planet’s distance from the Sun?

Artist 52 [7]

The farther from the sun an object is the larger the distance a planet has to orbit the sun. So if a planet is far from the sun the years would be longer. And if a planet is close to the sun it would be much hotter than a planet that is far from the sun.

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3 years ago

A 80 kg parent and a 20 kg child meet at the center of an ice rink. They place their hands together and push. The parent pushes

Ymorist [56]

Answer:

force acting on the parent = 25 N .

Explanation:

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3 years ago

Two charged objects separated by some distance attract each other. If the charges on both objects are doubled with no change in

beks73 [17]

Answer:

a. the force between them quadruples

Explanation:

The electrostatic force between two charges is given by

$F=k\frac{q_1 q_2}{r^2}$

where

k is the Coulomb's constant

q1 and q2 are the two charges

r is the separation between the two charges

In this problem, the charges on both objects are doubled, so

$q_1' = 2q_1\\q_2' = 2q_2$

While the distance does not change, so the new force will be

$F'= k \frac{(2q_1)(2q_2)}{r^2}=4 (k\frac{q_1 q_2}{r^2})=4 F$

so, the force will quadruple.

4 0

3 years ago

Please I need your help

frez [133]

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3 years ago

A single insulated duct flow experiment using air operating at steady-state is performed in a lab. One measurement location (Sta

weqwewe [10]

Answer:

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Explanation:

A free flow diagram of the horizontal insulated duct is as shown below.

NOW,

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$\frac{\sigma_{cv}}{m}= (s_2-s_1) \geq 0 \ \ \ -------> \ \ \ 1$