Answer: 588 joules
Explanation:
Work is done when force is applied on an object over a distance ( whether vertical or horizontal). It is measured in joules.
Thus, Workdone = Force X distance
- Vertical distance to be moved by the brick = 12 metres
- Mass of box = 5kg
- Acceleration due to gravity when box was lifted represented by g is a constant with value of 9.8m/s^2
Now, recall that Force = Mass x acceleration due to gravity
i.e Force = 5kg x 9.8m/s^2
Force = 49 Newton
So, Workdone = Force X Distance
Workdone = 49 Newton X 12 metres
Workdone = 588 joules
Thus, 588 joules of work was done.
v = f lambda
in vac ... 3X10^8 = 600x10^-9xf
in glass speed slower, poss 2/3 that of vacuum
Answer:
t = 2.13 10-10 s
, d = 6.39 cm
Explanation:
For this exercise we use the definition of refractive index
n = c / v
Where n is the refraction index, c the speed of light and v the speed in the material medium.
The refractive indices of ice and crown glass are 1.13 and 1.52, respectively, therefore the speed of the beam in the material medium is
v = c / n
As the beam strikes perpendicularly, the beam path is equal to the distance of the leaves, there is no refraction, so we can use the uniform motion relationships
v = d / t
t = d / v
t = d n / c
Let's look for the times on each sheet
Ice
t₁ = 1.4 10⁻² 1.31 / 3 10⁸
t₁ = 0.6113 10⁻¹⁰ s
Crown glass (BK7)
t₂ = 3.0 10⁻² 1.52 / 3.0 10⁸
t₂ = 1.52 10⁻¹⁰ s
Time is a scalar therefore it is additive
t = t₁ + t₂
t = (0.6113 + 1.52) 10⁻¹⁰
t = 2.13 10-10 s
The distance traveled by this time in a vacuum would be
d = c t
d = 3 10⁸ 2.13 10⁻¹⁰
d = 6.39 10⁻² m
d = 6.39 cm
A (b) would be 42 (c) from x to Y mark me as brainlist thanks
Answer:
Solenoid's inductance is 1.11 × 10^-8H
The average emf around the solenoid is 1.3 × 10^-5V
Explanation: Please see the attachments below
