<h2>Answer with Explanation </h2>
The Oscillating Universe Theory is a cosmological model that consolidates both the Big Bang and the Big Crunch as a major aspect of a repeating occasion. That is, in the event that this hypothesis remains constant, the Universe in which we live in exists between a Big Bang and a Big Crunch.
As such, our universe can be the first of a conceivable arrangement of universes or it tends to be the nth universe in the arrangement.
As we probably are aware, in the Big Bang Theory, the Universe is accepted to extend from a hot, exceptionally thick, and little element. Actually, on the off chance that we extrapolate back to the snapshot of the Big Bang, we can achieve a point of peculiarity described by unendingly high vitality and thickness, just as zero volume.
This portrayal would just mean a certain something every one of the laws of material science will be tossed out of the window. This is naturally unsuitable to physicists. To exacerbate the situation, a few cosmologists even trust that the Universe will, in the end, achieve the greatest purpose of development and that once this occurs, it will at that point crumple into itself.
This will basically prompt indistinguishable conditions from when we extrapolate back to the snapshot of the Big Bang. To cure this difficulty, a few researchers are suggesting that maybe the Universe won't achieve the purpose of peculiarity all things considered.
Answer:
We first to know that if the wheel rotates from rest means that at t=0 the velocity and the angle rotated is 0.
Then, we know:
Integrating 2 times, we have:
For the first 27.9 s, we have:
w = 37.107 rad/s
angle = 517.6426 rad
For the next seconds, according to the text, the angular velocity is constant so
w = 37.107 rad/s and hence, integrating:
Then, the time remaining is:
53.5 - 27.9 = 25.6
So for the next 25.6 seconds we have:
Finally, we add the 2 angles and we have as a result:
Answer:
Final temperature, T2 = 314.9 Kelvin
Explanation:
Given the following data:
Mass = 0.9kg
Initial temperature, T1 = 10°C to Kelvin = 10 + 273 = 283K
Quantity of heat = 120,000 J
Specific heat capacity = 4182 j/kgK
To find the final temperature;
Heat capacity is given by the formula;
Where;
Q represents the heat capacity or quantity of heat.
m represents the mass of an object.
c represents the specific heat capacity of water.
dt represents the change in temperature.
Making dt the subject of formula, we have;
Substituting into the equation, we have;
dt = 31.9K
Now, the final temperature T2 is;
But, dt = T2 - T1
T2 = dt + T1
T2 = 31.9 + 283
T2 = 314.9 Kelvin
Answer: 272.82 drop/tile
Explanation:
Given that the Rain drops fall on a tile surface at a density of 4638 drops/ft2. There are 17 tiles/ft2. How many drops fall on each tile?
Tiles/ft^2 × drop/tiles = drop/ft^2
Tiles will cancel out. Leaving the answer to be drop/ ft^2
Substitutes all the magnitude of the above units.
17 × drop/tiles = 4638
Make drop/tiles the subject of formula
Drop/tiles = 4638/17
Drop/tiles = 272.82
Therefore, 272.82 drop/tile drops fall on each tile?
