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3 years ago

15

A solution of sodium hydroxide was titrated against a solution of sulfuric acid. How many moles of sodium hydroxide would react

with 1 mole of sulfuric acid?

1 answer:

jeka57 [31]3 years ago

5 0

Answer:

2 mole of Sodium hydroxide reacts with 1 mole of Sulfuric acid

Explanation:

Write down the equation in the beginning with reactants and products:

NaOH + H₂SO₄ → Na₂SO₄ + H₂0

Now try to balance it. Try with Na first:

2NaOH + H₂SO₄ → Na₂SO₄ + H₂0

Na atoms are balanced. There are 6 Oxygen atoms on the right and 5 on the left. Balance by increasing the H₂O moles:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂0

Check if H atoms are also balanced. They are. That means our final reaction is:

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂0

2 Moles of NaOH reacts with 1 mole of H₂SO₄

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The two sides of the equation should be

KonstantinChe [14]

Answer:

Hey mate.....

Explanation:

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hope it helps,

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3 years ago

Read 2 more answers

A 19-g piece of metal absorbs 186.75 joules of heat energy, and its temperature changes from 35°C to 175°C. Calculate the specif

slavikrds [6]

Answer:

0.0702J/g°C the specific heat capacity of the metal.

Explanation:m

$Q=m\times c\times \Delta T=m\times c\times (T_{2}-T_{1})$

where,

Q = heat absorbed by metal = 186.75 J

$m_1$ = Mass of metal= 19 g

$T_1$ = Initial temperature of metal = $35^oC$

$T_2$ =Final temperature of metal = $175^oC$

$c$ = specific heat of metal= ?

$186.75 J=19 g\times c\times (175^oC-35^oC)$

$c=\frac{186.75 J}{19 g\times (175^oC-35^oC)}$

$c=0.0702J/g^oC$

0.0702J/g°C the specific heat capacity of the metal.

6 0

3 years ago

How many atoms are in 25.00 g of B.

iren2701 [21]

Answer:

$\boxed {\boxed {\sf 1.393 *10^{24} \ atoms \ B}}$

Explanation:

<u>1. Convert Grams to Moles</u>

Use the molar mass (found on the Periodic Table) to convert from grams to moles.

Boron (B): 10.81 g/mol

Use this value as a ratio.

$\frac {10.81 \ g \ B }{1 \ mol \ B}$

Multiply by the given number of grams.

$25.00 \ g \ B *\frac {10.81 \ g \ B }{1 \ mol \ B}$

Flip the ratio so the grams of boron cancel out.

$25.00 \ g \ B *\frac {1 \ mol \ B }{10.81 \ g \ B}$

$25.00 *\frac {1 \ mol \ B }{10.81 }$

$\frac {25.00 \ mol \ B }{10.81 }=2.312673451 \ mol \ B$

<u>2. Convert Moles to Atoms</u>

We use Avogadro's Number, 6.02*10²³: the number of particles (atoms, molecules, etc.) in 1 mole of a substance. In this case, the particles are atoms of boron.

$\frac {6.02*10^{23} \ atoms \ B} {1 \ mol \ B}$

Multiply by the number of moles we calculated.

$2.312673451 \ mol \ B *\frac {6.02*10^{23} \ atoms \ B} {1 \ mol \ B}$

The moles of boron cancel.

$2.312673451 *\frac {6.02*10^{23} \ atoms \ B} {1 }$

$2.312673451 *6.02*10^{23} \ atoms \ B} =1.39269195*10^{24} \ atoms \ B$

The original value of grams has 4 significant figures, so our answer should have the same. For the number we calculated, that is the thousandth place.

$1.392\underline69195*10^{24} \ atoms \ B$

The 6 tells us to round the 2 to a 3.

$1.393 *10^{24} \ atoms \ B$

25.00 grams of boron is equal to 1.393*10²⁴ atoms.

6 0

3 years ago

#1: A material has a density of 8.9 g/cm^3. You have six cubic centimeters of the substance. What is the material’s mass in gram

sveta [45]

<span>The density of a material = mass/ volume From the question, volume = 6 cm^3. Since the density = 8.9 g/cm^3 We have that 8.9 = mass/ 6 So mass = 8.9 * 6 = 53.4 So it follows that our mass = 53.4g. Hence option D which is 53g.</span>

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3 years ago

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What what is the equation for percent error

Stella [2.4K]

When you calculate results that are aiming for known values, the percent error formula is useful tool for determining the precision of your calculations. The formula is given by: The experimental value is your calculated value, and the theoretical value is your known value.

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3 years ago