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3 years ago

Need to find A, B, and C!

Mathematics

2 answers:

Lana71 [14]3 years ago

8 0

Answer:

A. Mean = $41900

B. Median = $37000

C. Mode = $37000

Step-by-step explanation:

A. Mean

Here

n=40

Mean = Sum of values/n

$Mean = \frac{(3)(18000)+(3)(22000)+(3)(25000)+(5)(34000)+(17)(37000)+(2)(45000)+52000+(5)(80000)+140000}{40}\\=\frac{54000+66000+75000+170000+629000+90000+52000+400000+140000}{40} \\=\frac{1676000}{40}\\=41900$

Mean = $41900

B. Median:

As the number of salaries is even,

the median will be mean of middle two terms

$Median= \frac{1}{2}(\frac{n}{2}th\ term+ \frac{n+2}{2}th\ term)\\= \frac{1}{2}(\frac{40}{2}th\ term+ \frac{40+2}{2}th\ term)\\=\frac{1}{2} (20th + 21st)}\\$

The 20th and 21st term will be 37000

So their mean will be same

So,

Median = $37000

C. Mode

Mode is the value which occurs most of the time in data.

the occurrence of 37000 is highest in the given data.

So,

Mode = $37000 ..

gtnhenbr [62]3 years ago

7 0

Answer:

Mean: 4.44 add up every number and divide it by how many there is.

Median: 3 put from least to greatest and count till the middle.

Mode: 3 because it appears the most

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Substitute x+y =200 9.5x+27y=4000

Vera_Pavlovna [14]

Point form: (80,120)
X=80, Y=120

3 0

3 years ago

solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars

Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

Every x has only one value of y

x appears once in ordered pairs

Examples:

The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)

The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)

The domain is the set of values of x

The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

3 0

2 years ago

Sora was given two data sets, one without an outlier and one with an outlier. Data without an outlier: 108, 113, 105, 118, 124,

gladu [14]

The outlier (61) is at the low end of the data set, but doesn't affect the mean by a lot, so ...

The mean is centered among the other numbers in both sets of data.

_____

The mean without the outlier is 114. With the outlier, it is 107.4. The lower quartile is 108, so the mean does get moved outside the "box" of the box-and-whisker plot of the data set without the outlier.

8 0

3 years ago

Read 2 more answers

En una caja de cartón se empacan 400 latas de atún al acomodarlas resultan que caben 5 latas más a lo largo que a lo ancho y a l

Anvisha [2.4K]

Answer:

Hay 50 latas en total que tocan el fondo de la caja.

Step-by-step explanation:

Una caja de cartón es representada por un cuadrilátero, cuyas caras son rectángulos. Si la caja esta ocupada por completo, entonces la cantidad total de latas es representada por la siguiente expresión:

$n_{V} = n_{w}\cdot n_{h}\cdot n_{l}$ (1)

Donde:

$n_{V}$ - Total de latas de atún, adimensional.

$n_{w}$ - Cantidad de latas de atún a lo ancho de la caja, adimensional.

$n_{h}$ - Cantidad de latas de atún a lo alto de la caja, adimensional.

$n_{l}$ - Cantidad de latas de atún a lo largo de la caja, adimensional.

De acuerdo con el enunciado, tenemos las siguientes relaciones:

$n_{V} = 400$ (2)

$n_{l} = n_{w} +5$ (3)

$n_{h} = n_{w}+3$ (4)

Si aplicamos estas fórmulas a (1), tenemos el siguiente polinomio de tercer orden:

$n_{w} \cdot (n_{w}+5)\cdot (n_{w}+3) = 400$

$n_{w}\cdot (n_{w}^{2}+8\cdot n_{w}+15) = 400$

$n_{w}^{3}+8\cdot n_{w}^{2}+15\cdot n_{w} -400 = 0$

Este polinomio se puede resolver por vía analítica por el Método de Cardano o por vía numérica, sus raíces son:

$n_{w,1} = 5$ , $n_{w,2} = -6.5+i\,6.144$ , $n_{w,3} = -6.5-i\,6.144$

En consecuencia, la única solución válida es $n_{w} = 5$ y las variables restantes son por (3) y (4):

$n_{l} = 10$ y $n_{h} = 8$

La cantidad de latas que tocan el fondo de la caja es igual al producto de la cantidad de latas a lo largo de la caja y la cantidad de latas a lo ancho de la caja, es decir:

$n_{A} = n_{w}\cdot n_{l}$ (5)

$n_{A} = (5)\cdot (10)$

$n_{A} = 50$

Hay 50 latas en total que tocan el fondo de la caja.

4 0

2 years ago

In an endurance race, Alyson rode her bicycle 7 miles less than Jeff. Together they rode 39 miles. How far did Alyson ride?

morpeh [17]

Answer:

Distance cover by Alyson = 16 miles

Step-by-step explanation:

Given:

Distance cover together = 39 miles

Assume;

Distance cover by Jeff = a

Distance cover by Alyson = a - 7

Find:

Distance cover by Alyson

Computation:

a + (a - 7) = 39

2a - 7 = 39

2a = 46

a = 23

Distance cover by Alyson = a - 7

Distance cover by Alyson = 23 - 7

Distance cover by Alyson = 16 miles

5 0

3 years ago