The area of the given trapezoid will be the sum of the areas of the triangular part and the rectangular part.
Now, the area of the rectangle, 
is:
squared yards
Likewise, the area, 
of the triangle will be:
Thus, the area of the trapezoid=
Thus the first option is the correct option.
Answer: SU = 4(1) + 1 = 5
Step-by-step explanation:
Since T is on segment SU we know the whole is eqaul to the sum of it’s parts.
ST + TU = SU substitute
3x - 1 + 3x = 4x + 1 simplify
6x - 1 = 4x + 1 solve for x
2x = 2
x = 1
ST = 3(1) -1 = 2
TU = 3(1) = 3
SU = 4(1) + 1 = 5
It is 5/3 !! 8^(5/3)=....32!
Answer:
Mean track length for this rock specimen is between 10.463 and 13.537
Step-by-step explanation:
99% confidence interval for the mean track length for rock specimen can be calculated using the formula:
M±
where
- M is the average track length (12 μm) in the report
- t is the two tailed t-score in 99% confidence interval (2.977)
- s is the standard deviation of track lengths in the report (2 μm)
- N is the total number of tracks (15)
putting these numbers in the formula, we get confidence interval in 99% confidence as:
12±
=12±1.537
Therefore, mean track length for this rock specimen is between 10.463 and 13.537
Answer:
1. .900+.020+.008, 2. .700+.030+.001, 3. 4.5, 4.56, 4.565656, 4.6
Step-by-step explanation:
