For this case , the parent function is given by [tex f (x) =x^2
[\tex]
We apply the following transformations
Vertical translations :
Suppose that k > 0
To graph y=f(x)+k, move the graph of k units upwards
For k=9
We have
[tex]h(x)=x^2+9
[\tex]
Horizontal translation
Suppose that h>0
To graph y=f(x-h) , move the graph of h units to the right
For h=4 we have :
[tex ] g (x) =(x-4) ^ 2+9
[\tex]
Answer :
The function g(x) is given by
G(x) =(x-4)2 +9
Answer:

Step-by-step explanation:
{y = 6x − 11
{y = x² + 4x − 10
x² + 4x − 10 = 6x − 11
- [6x − 11] - [6x − 11]
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x² - 2x + 1
![{[x - 1]}^{2} = 0](https://tex.z-dn.net/?f=%7B%5Bx%20-%201%5D%7D%5E%7B2%7D%20%3D%200)
1 = x [Plug this back into both equations above to get the y-coordinate of −5]; −5 = y
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Answer:
2
Step-by-step explanation:

![\sqrt[3]{8} = 2](https://tex.z-dn.net/?f=%20%5Csqrt%5B3%5D%7B8%7D%20%20%3D%202)