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Masja [62]
3 years ago
9

What velocity does a 2kg mass have when its kinetic energy is 16 J

Physics
1 answer:
alexandr402 [8]3 years ago
7 0
We can use the equation for kinetic energy, K=1/2mv².
Your given variables are already in the correct units, so we can just plug in the variables and solve for v. 

K = 1/2mv²
16 = 1/2(2)v²
16 = (1)v²
√16 = v
v = 4 m/s

Therefore, the velocity of a 2 kg mass with 16 J of kinetic energy is 4 m/s.
Hope this is helpful!
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Arigid body must rotate about an axis in order for it to have angular momentum about that axis. True False
kompoz [17]

Answer:

False

Explanation:

Let's consider the definition of the angular momentum,

\vec{L} = I \vec{\omega}

where I = \int\limits_m r^2 dm = \lim_{n \to \infty} \sum\limits_{i=1}^n m_i r_i^2 is the moment of inertia for a rigid body. Now, this moment of inertia could change if we change the axis of rotation, because "r" is defined as the distance between the puntual mass and the nearest point on the axis of rotation, but still it's going to have some value. On the other hand,

\vec{\omega} = \frac{\vec{r} \times \vec{v}}{r^2} so \vec{\omega} \neq 0 unless \vec{r} ║  \vec{v}.

In conclusion, a rigid body could rotate about certain axis, generating an angular momentum, but if you choose another axis, there could be some parts of the rigid body rotating around the new axis, especially if there is a projection of the old axis in the new one.

7 0
3 years ago
The rocket is fired vertically and tracked by the radar station shown. When θ reaches 66°, other corresponding measurements give
Flauer [41]

Answer:

velocity = 1527.52 ft/s

Acceleration = 80.13 ft/s²

Explanation:

We are given;

Radius of rotation; r = 32,700 ft

Radial acceleration; a_r = r¨ = 85 ft/s²

Angular velocity; ω = θ˙˙ = 0.019 rad/s

Also, angle θ reaches 66°

So, velocity of the rocket for the given position will be;

v = rθ˙˙/cos θ

so, v = 32700 × 0.019/ cos 66

v = 1527.52 ft/s

Acceleration is given by the formula ;

a = a_r/sinθ

For the given position,

a_r = r¨ - r(θ˙˙)²

Thus,

a = (r¨ - r(θ˙˙)²)/sinθ

Plugging in the relevant values, we obtain;

a = (85 - 32700(0.019)²)/sin66

a = (85 - 11.8047)/0.9135

a = 80.13 ft/s²

4 0
3 years ago
You want to raise the temperature of 22kg of water from 60°C to 95°C. If electricity costs $0.08/kWh, how much would it cost you
Sladkaya [172]

Answer:

dgtgh

Explanation:

dgdfhdhfffff thdhfghjfj e

3 0
3 years ago
the car turned a corner going 10m/s if it took two seconds to turn what is its acceleration is this acceleration​
exis [7]

The acceleration of this car is equal to 5 m/s^2.

<u>Given the following data:</u>

  • Initial velocity = 0 m/s (assuming it's starting from rest).
  • Final velocity = 10 m/s.
  • Time = 2 seconds.

To determine the acceleration of this car:

<h3>How to calculate acceleration.</h3>

In Science, the acceleration of an object is calculated by subtracting the initial velocity from its final velocity and dividing by the time.

Mathematically,  acceleration is given by this formula:

a = \frac{V\;-\;U}{t}

<u>Where:</u>  

  • V is the final velocity.
  • U is the initial velocity.
  • is the time measured in seconds.

Substituting the given parameters into the formula, we have;

a = \frac{10\;-\;0}{2}

Acceleration, a = 5 m/s^2

Read more on acceleration here: brainly.com/question/24728358

6 0
2 years ago
A basketball has a mass of 567 g. Heading straight downward, in the direction, it hits the floor with a speed of 2 m/s and rebou
Vsevolod [243]

Answer:

\Delta p=2.27\frac{kg\cdot m}{s}

Explanation:

The momentum change is defined as:

\Delta p=p_f-p_i\\\Delta p=mv_f-mv_i\\\Delta p=m(v_f-v_i)(1)

Taking the downward motion as negative and the upward motion as positive, we have:

v_f=2\frac{m}{s}(2)\\v_i=-2\frac{m}{s}(3)

Replacing (2) and (3) in (1):

\Delta p=567*10^{-3}kg(2\frac{m}{s}-(-2\frac{m}{s}))\\\Delta p=2.27\frac{kg\cdot m}{s}

5 0
3 years ago
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