Question

Percent Composition Calculations

Answer 1

Answer:

$\boxed{\text{17.76 \% by mass}}$

Explanation:

$\text{The mass of one molecule of NH _{3} is:}\\\text{14.01 u N + 3.024 u H = 17.034 u}\\\\\text{mass \% H} =\dfrac{3.024}{17.034} \times 100 \%} =\textbf{17.76 \%}\\\\\text{Ammonia contains }\boxed{\textbf{17.76 \% H by mass}}$