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3 years ago

8

During a volcanic eruption, large amounts of poisonous gases and particles are released into the atmosphere. How do some of thes

e gases eventually reach the Earth's surface?
A) through rain
B) through wind
C) through lava
D) through trees

1 answer:

xz_007 [3.2K]3 years ago

3 0

A through rain because it is:)

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If this compounds (N2O) molecular mass is 88g are the empirical and molecular formulas the same as one another or different

Softa [21]

Answer:

No

Explanation:

Let us examine this problem carefully:

Given compound is N₂O

Molecular mass = 88g

Now,

The empirical formula is the simplest formula of a compound.

The molecular formula is the true formula of the compound that shows that actual ratios of the atoms in a compound.

To find if they both have the same molecular and empirical formula, they must have the same molecular mass.

For N₂O;

Molecular mass = 2(14) + 16 = 44g/mole

But the true and given molecular formula of the compound is 88g/mole

This shows that the compound given is the empirical formula of the compound.

Molecular formula:

molecular mass of empirical formula x n = molecular mass of molecular formula

n = $\frac{88}{44}$ = 2

Molecular formula of compound = 2(N₂O) = N₄O₂

Therefore the empirical and molecular formulas are not the same

8 0

3 years ago

What is the final temperature in ∘c if the process is isothermal?

VikaD [51]

0.014 mol of gas undergoes the process shown in the figure (Figure 1) .

5 0

3 years ago

What pressure (in kilopascals) is exerted by 4.20 moles of Xenon gas in a 15.0 L container at 280.0 K?

aniked [119]

Answer: the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa

Explanation:

The question requires us to calculate the pressure, in kPa, connsidering the following information:

<em>number of moles = n = 4.20mol</em>

<em>volume of gas = V = 15.0L</em>

<em>temperature of gas = T = 280.0 K</em>

We can use the equation of ideal gases to calculate the pressure of the gas, as shown by the rearranged equation below:

$PV=nRT\rightarrow P=\frac{nRT}{V}$

Since the volume was given in L and the question requires us to calculate the pressure in kPa, we can use R in units of L.Pa/K.mol:

<em>R = 8314.46 L.Pa/K.mol</em>

Applying the values given by the question to the rearranged equation above, we'll have:

$\begin{gathered} P=\frac{nRT}{V} \\ \\ P=\frac{(4.20mol)\times(8314.46L.Pa/K.mol)\times(280.0K)}{(15.0L)}=652\times10^3Pa \end{gathered}$

Therefore, the pressure exerted by the gas is 652 x 10^3 Pa, which corresponds to 652 kPa.

8 0

1 year ago

jeka57 [31]

I think it is C. i took a quiz on that.

3 0

3 years ago

A sheet of aluminum foil has a total area of 1.000 m2 and a mass of 3.636 g. What is the thickness of the sheet in millimeters?

olga2289 [7]

Answer:

$t=1.34\times 10^{-3}\ mm$

Explanation:

Given that,

Area of sheet of Aluminium foil is 1 m²

Mass of the sheet = 3.636 g

The density of Aluminium, $d=2.699\ g/cm^3$

We need to find the thickness of the sheet in millimeters.

The density of an object is given in terms of its mass and volume as follows :

$d=\dfrac{m}{V}$

V = volume, V = A×t, t = thickness of the sheet

So,

$d=\dfrac{m}{A\times t}\\\\t=\dfrac{m}{Ad}\\\\t=\dfrac{3.636\ g}{10000\ cm^2\times 2.699\ g/cm^3}\\\\t=0.000134\ cm$

Since, 1 cm = 10 mm

So,

t = 0.00134 mm

or

$t=1.34\times 10^{-3}\ mm$

8 0

3 years ago