<u>Answer:</u> The concentration of original sulfuric acid solution is 1.62 M
<u>Explanation:</u>
Let the original concentration of sulfuric acid be 'x' M
To calculate the molarity of the diluted solution, we use the equation:

where,
are the molarity and volume of the concentrated sulfuric acid solution
are the molarity and volume of diluted sulfuric acid solution
We are given:

Putting values in above equation, we get:

Now, to calculate the concentration of acid, we use the equation given by neutralization reaction:

where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is NaOH.
We are given:

Putting values in above equation, we get:

Hence, the concentration of original sulfuric acid solution is 1.62 M