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Lostsunrise [7]
3 years ago
7

What are some types of landforms on Earth’s surface? PLS ANSWER QUICK 11 POINTS

Physics
2 answers:
Brrunno [24]3 years ago
5 0

Answer:

plateau, mountains, hills, plains

DochEvi [55]3 years ago
4 0
Plateau, butte, canyon, valley, mountain, hill
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Match the terms to the correct descriptions. Question 1 options:
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1) Refraction
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I took the test and got this right so you can believe me :)
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3 years ago
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3. Identify the structures of the skin by the labels A through G below
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An object is placed on a surface. A student tries to apply various combinations of forces on the object. Which pair of forces wi
AVprozaik [17]

Answer:

See Explanation

Explanation:

The question is incomplete, as there are no diagrams or options to provide more information to the question.

The general explanation is as follows:

For the object not to move

(1): The forces acting on the object must opposite each other. i.e. if force A acts at the right (or positive direction), force B will act at the left (or negative direction).

(2) The two forces must be equal.

So, for instance:

If the pair of forces are 5N and 5N in opposite directions, the object wil not move.

However, if one of the forces is greater, the object will move towards the direction of the greater force.

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2 years ago
Which is the BEST description of how eyeglasses work?
Sonbull [250]

Answer:

C I think.

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3 years ago
The center of the Hubble space telescope is 6940 km from Earth’s center. If the gravitational force between Earth and the telesc
Law Incorporation [45]
The gravitational force between two objects is given by:
F=G \frac{m_1 m_2}{r^2}
where
G is the gravitational constant
m1 and m2 are the masses of the two objects
r is the separation between the two objects

The distance of the telescope from the Earth's center is r=6940 km=6.94 \cdot 10^6 m, the gravitational force is F=9.21 \cdot 10^4 N and the mass of the Earth is m_1=5.98 \cdot 10^{24} kg, therefore we can rearrange the previous equation to find m2, the mass of the telescope:
m_2 =  \frac{Fr^2}{Gm_1}= \frac{(9.21 \cdot 10^4 N)(6.94\cdot 10^6)^2}{(6.67\cdot 10^{-11})(5.98\cdot 10^{24})} =11121 kg
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3 years ago
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