It would be C because that is the one that make the most sense
We are given the function:
g(x) = 6 (4)^x
Part A.
To get the average rate of change, we use the formula:
average rate of change = [g(x2) – g(x1)] / (x2 – x1)
Section A:
average rate of change = [6 (4)^1 – 6 (4)^0] / (1 – 0) =
18
Section B:
average rate of change = [6 (4)^3 – 6 (4)^2] / (3 – 2) =
288
Part B.
288 / 18 = 16
Therefore the average rate of change of Section B is 16 times
greater than in Section A.
<span>The average rate of change is greater between x = 2 to x = 3 than between
x = 1 and x = 0 because an exponential function's rate of change increases
with increasing x (not constant).</span>
Answer:
1.148698
Step-by-step explanation:
I'm not sure what this means. If you have choices you should list them.
(1/2)*(1/4 + 1/6) is an example of what should be given. There are two ways to solve this.
1. Use the distributive property.
1/2*1/4 + 1/2* 1/6
1/8 + 1/12 Which can be added using the LCD of 24
3/24 + 2/24 = 5/24
Method 2
Add what is inside the brackets first.
1/2 ( 1/4 + 1/6)
1/2(3/12 + 2/12 = 5/12
Now multiply by 1/2
1/2(5/12) = 5*1/(12 * 2) = 5 / 24 Same answer.
Answer with explanation:
Class Interval Variate Frequency
16-18 16 1
19-21 0 0
22-24 0 0
25-27 26,27 2
